shellscript中的$ {param ##}和$ {param $$}是什么意思

时间:2020-10-29 03:05:03

标签: linux shell unix db2

在我浏览一些现有脚本时,我是Shell脚本的新手。我了解以下命令

db2 -x some command | read
    param
    param=${param## }; 
    param=${param%% };

任何人都可以通过它来理解

1 个答案:

答案 0 :(得分:0)

在bash手册页中:

${parameter##word}
          Remove matching prefix pattern.  The word is expanded to produce
          a pattern just as in pathname expansion.  If the pattern matches
          the beginning of the value of parameter, then the result of  the
          expansion  is  the expanded value of parameter with the shortest
          matching pattern (the ``#'' case) or the longest  matching  patâ
          tern  (the  ``##''  case)  deleted.  If parameter is @ or *, the
          pattern removal operation is applied to each positional  parameâ
          ter in turn, and the expansion is the resultant list.  If paramâ
          eter is an array variable subscripted with @ or *,  the  pattern
          removal  operation  is  applied  to  each member of the array in
          turn, and the expansion is the resultant list.

 ${parameter%%word}
          Remove matching suffix pattern.  The word is expanded to produce
          a pattern just as in pathname expansion.  If the pattern matches
          a trailing portion of the expanded value of parameter, then  the
          result  of the expansion is the expanded value of parameter with
          the shortest matching pattern (the ``%'' case)  or  the  longest
          matching  pattern  (the ``%%'' case) deleted.  If parameter is @
          or *, the pattern removal operation is  applied  to  each  posiâ
          tional  parameter  in  turn,  and the expansion is the resultant
          list.  If parameter is an array variable subscripted with  @  or
          *,  the  pattern  removal operation is applied to each member of
          the array in turn, and the expansion is the resultant list.

因此,总而言之,请牢记您的示例,param = $ {param ##};将删除变量param中的前导空格,而$ {parameter %% word}将删除尾部空格