字符串熊猫中的正则表达式（拆分）

Question

你好，我有一个字符串，例如：

liste_to_split=['NW_011625257.1_0','scaffold1_3','scaffold3']

，我想在Number_Number拆分它们 我尝试过：

for i in liste_to_split:
 i.split(r'(?<=[0-9])_')

我知道了

['NW_011625257.1_0']
['scaffold1_3']
['scaffold3']

代替

['NW_011625257.1'] ['0']
['scaffold1'] ['3']
['scaffold3']

有人知道问题出在哪里吗？

Answer 1

您可以使用：

>>> import re
>>> liste_to_split=['NW_011625257.1_0','scaffold1_3','scaffold3']
>>> 
>>> for i in liste_to_split:
...     re.split(r'(?<=[0-9])_', i)
...
['NW_011625257.1', '0']
['scaffold1', '3']
['scaffold3']

请注意使用re.split而不是string.split，并在断言后方使用_来确保我们不会在零宽度匹配上进行分割。

---

根据OP在下面的评论，看来OP希望对dataframe列进行此拆分。在这种情况下，请使用：

假设这是您的数据框：

>>> print (df)
             column
0  NW_011625257.1_0
1       scaffold1_3
2         scaffold3

然后您可以使用：

>>> print (df['column'].str.split(r'(?<=[0-9])_', expand=True))
                0     1
0  NW_011625257.1     0
1       scaffold1     3
2       scaffold3  None

Answer 2

l=['NW_011625257.1_0','scaffold1_3','scaffold3']

for i in l:
  f = i.split('_')
  print(f) 

输出

['NW', '011625257.1', '0']
['scaffold1', '3']
['scaffold3']