我正在尝试使用peer / getUserMedia创建视频会议Web应用。
当前，当我向视频会议发送唯一ID时，我能够听到/看到任何参加我的会议的人。
但是，只有第一个参加我的会议的人可以交流/见我。
我想这样做，以便其他用户也可以看到/听到视频会议中的每个用户。
到目前为止，这是我到目前为止的工作。还有当前编写的代码，只要有新用户加入，我的视频就会再次添加，因此我可以看到自己的两个视频（如果是主持人），但这对我来说很容易
<html>
<body>
<h3 id="show-peer"></h3>
<div style="display: grid; justify-content: space-around; margin:10px;">
<div style="width: 300px;height: 200px;transform: scale(-1, 1);border: 2px solid; display:grid; margin-bottom: 5%;" id="ourVideo"></div>
<div style="width: 300px;height: 200px;transform: scale(-1, 1);border: 2px solid; display: grid;" id="remoteVideo"></div>
</div>
<input id="peerID" placeholder="Peer ID">
<button id="call-peer" onclick="callPeer()">Call Peer</button>
<br>
<button id="screenShare"onclick="shareScreen()">Share Screen</button>
</body>
<script src="https://unpkg.com/peerjs@1.3.1/dist/peerjs.min.js"></script>
<script>
window.addEventListener('load',(event)=>{
var peer= new Peer()
var myStream;
var currentPeer;
var peerList=[];
peer.on('open',function(id){
document.getElementById("show-peer").innerHTML=id
})
peer.on('call',function(call){
navigator.mediaDevices.getUserMedia({
video:true,
audio:true
}).then((stream)=>{
myStream = stream
addOurVideo(stream)
call.answer(stream)
call.on('stream',function(remoteStream){
if(!peerList.includes(call.peer)){
addRemoteVideo(remoteStream)
currentPeer = call.peerConnection
peerList.push(call.peer)
}
})
}).catch((err)=>{
console.log(err+" unable to get media")
})
})
function stopScreenShare(){
let videoTrack = myStream.getVideoTracks()[0];
var sender = currentPeer.getSenders().find(function(s){
return s.track.kind ==videoTrack.kind;
})
sender.replaceTrack(videoTrack)
};
document.getElementById("call-peer").addEventListener('click',(e)=>{
let remotePeerId= document.getElementById("peerID").value;
document.getElementById("show-peer").innerHTML= "connecting "+remotePeerId;
console.log(remotePeerId)
callPeer(remotePeerId);
})
document.getElementById("screenShare").addEventListener('click',(e)=>{
navigator.mediaDevices.getDisplayMedia({
video: {
cursor: "always"
},
audio:{
autoGainControl: false,
echoCancellation: false,
googAutoGainControl: false,
noiseSuppression: false
}
}).then((stream)=>{
let videoTrack = stream.getVideoTracks()[0];
videoTrack.onended = function(){
stopScreenShare()
}
let sender = currentPeer.getSenders().find(function(s){
return s.track.kind == videoTrack.kind
})
sender.replaceTrack(videoTrack)
}).catch((err)=>{
console.log("unable to get display media"+err)
})
})
function callPeer(id){
navigator.mediaDevices.getUserMedia({
video:true,
audio:true
}).then((stream)=>{
myStream = stream
addOurVideo(stream)
let call = peer.call(id,stream)
call.on('stream',function(remoteStream){
if(!peerList.includes(call.peer)){
addRemoteVideo(remoteStream)
currentPeer = call.peerConnection
peerList.push(call.peer)
}
})
}).catch((err)=>{
console.log(err+" unable to get media")
})
}
function addRemoteVideo(stream){
let video = document.createElement("video");
video.classList.add("video")
video.srcObject = stream;
video.play()
document.getElementById("remoteVideo").append(video)
}
function addOurVideo(stream){
let video = document.createElement("video");
video.classList.add("video")
video.srcObject = stream;
video.play()
video.muted=true;
document.getElementById("ourVideo").append(video)
}
});
</script>
</html>
答案 0 :(得分：1)
我认为您将需要创建一个“网格”。因此，在3个对等方的情况下，每个用户（对等方）都建立了两个连接，一个连接至其他两个用户。在每个客户端的一端，都有两个完全不同的连接。
用户@daGrevis在PeerJs GitHub上问this question。最终，这是他们用于多点聊天的实现，可能会有所帮助：
Chat = React.createClass
displayName: "Foo"
getInitialState: ->
messages: []
connectionsToPeerIds: (connections) ->
_.map connections, (connection) => connection.peer
componentWillMount: ->
who = getSegments()[1]
peer = new Peer who, key: PEER_KEY, debug: 2
@connections = []
peer.on "error", (error) =>
alert error.type
peer.on "open", (peerId) =>
if who == "x"
peer.on "connection", (connection) =>
@connections.push connection
@listenForMessage connection
peerIds = @connectionsToPeerIds @connections
connection.on "open", =>
connectionsWithoutNewConnection = _.filter @connections, (c) -> c.peer != connection.peer
peerIdsWithoutNewConnection = @connectionsToPeerIds connectionsWithoutNewConnection
if peerIdsWithoutNewConnection.length
connection.send type: "newConnection", peerIds: peerIdsWithoutNewConnection
if who != "x"
connection = peer.connect "x"
connection.on "error", (error) =>
alert error
connection.on "open", =>
@connections.push connection
@listenForMessage connection
connection.on "data", (data) =>
if data.type == "newConnection"
peerIds = data.peerIds
_.forEach peerIds, (peerId) =>
connection = peer.connect peerId
do (connection) =>
connection.on "error", (error) =>
alert error.type
connection.on "open", =>
@connections.push connection
@listenForMessage connection
peer.on "connection", (connection) =>
connection.on "open", =>
@connections.push connection
@listenForMessage connection
然后我找到了一个实例，其中用户@mluketin使用peerjs-server，并创建了电话会议示例https://github.com/mluketin/peerjs-helloworld-conference
根据我所了解和阅读的内容，看起来网状设计是最简单的方法，但仅限于速度最慢的同级对象。因此，如果您只需要3-5个人，那应该没问题。否则，您可能必须遵循mluketin布置的示例。
更多可能有用的链接：