SQL Server PIVOT问题

时间:2011-06-23 14:34:24

标签: sql-server tsql

对于我的生活,我无法看到我在这里做错了什么。

SELECT Series_ID
       , 1 AS Jan
       , 2 AS Feb
       , 3 AS Mar
       , 4 AS Apr
       , 5 AS May
       , 6 AS Jun
       , 7 AS Jul
       , 8 AS Aug
       , 9 AS Sep
       , 10 AS Oct
       , 11 AS Nov
       , 12 AS [Dec]
FROM 
  (
    SELECT MONTH(ActionDate_DT) AS [MonthNum]
         , Series_ID
         , ID
      FROM TasksSeries_V
     WHERE Series_ID IN (5632751,5672397,5680669,5680670,5632713,5632752,5680902)
           AND  TasksSeries_V.ActionDate_DT BETWEEN '01 Jan 2011' AND '31 Dec 2011'
  ) AS SourceTable
PIVOT 
  (
COUNT(ID) FOR MonthNum IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12])
  ) AS pvt   

当我跑步时,我得到

ID      Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
5632713 1   2   3   4   5   6   7   8   9   10  11  12
5632751 1   2   3   4   5   6   7   8   9   10  11  12
5632752 1   2   3   4   5   6   7   8   9   10  11  12
5672396 1   2   3   4   5   6   7   8   9   10  11  12
5672397 1   2   3   4   5   6   7   8   9   10  11  12
5680669 1   2   3   4   5   6   7   8   9   10  11  12
5680670 1   2   3   4   5   6   7   8   9   10  11  12
5680902 1   2   3   4   5   6   7   8   9   10  11  12

有什么想法吗?

2 个答案:

答案 0 :(得分:2)

我认为问题在于,在第一个SELECT语句中,您应该使用[1]而不是1作为列名。

SELECT Series_ID
       , [1] AS Jan
       , [2] AS Feb
       , [3] AS Mar
       , [4] AS Apr
       , [5] AS May
       , [6] AS Jun
       , [7] AS Jul
       , [8] AS Aug
       , [9] AS Sep
       , [10] AS Oct
       , [11] AS Nov
       , [12] AS [Dec]
FROM 
  (
    SELECT MONTH(ActionDate_DT) AS [MonthNum]
         , Series_ID
         , ID
      FROM TasksSeries_V
     WHERE Series_ID IN (5632751,5672397,5680669,5680670,5632713,5632752,5680902)
           AND  TasksSeries_V.ActionDate_DT BETWEEN '01 Jan 2011' AND '31 Dec 2011'
  ) AS SourceTable
PIVOT 
  (
      COUNT(ID) 
        FOR MonthNum IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12])
  ) AS pvt   

答案 1 :(得分:0)

该行

SELECT Series_ID, 1 AS Jan, 2 AS Feb, 3 AS Mar, 4 AS Apr, 5 AS May, 6 AS Jun, 7 AS Jul, 8 AS Aug, 9 AS Sep, 10 AS Oct, 11 AS Nov, 12 AS [Dec]

表示我们应该选择文字值1和别名为Jan,文字值2和别名为Feb ...而是通过用方括号或双引号括起来引用名为1的列

SELECT Series_ID, [1] AS Jan, [2] AS Feb, [3] AS Mar, [4] AS Apr, [5] AS May, [6] AS Jun, [7] AS Jul, [8] AS Aug, [9] AS Sep, [10] AS Oct, [11] AS Nov, [12] AS [Dec]