Question

我有一个简单的嵌套while循环情况，但是我不确定如何在第二个循环内增加numGuesses以便在不小于5的情况下退出第一个循环。

while(numGuesses<5){
    while(!correct){
        cout << "\nGuess the number the computer randomply picked between 1 - 100: ";
        numGuesses++;
        cin >> guess;
        if(guess<number){
            cin.clear(); //clears input stream
            cin.ignore(256, '\n');
            cout << "\nSorry, your guess is too low";
        }
        else if (guess>number){
            cout << "\nSorry, your guess is too high";
        }
        else{
            cout << "\nYou guessed right, you win!";
            correct = !correct;
        }
    }
    
}
cout << "Sorry, you lost. The number is: " << number;

每次内部while循环迭代时，我都希望numGuesses增加，但是我猜它不在其范围内吗？对不起，菜鸟问题。完整代码：https://ctxt.io/2/AAAgfdIGEg

Answer 1

您应该只使用一个while循环！毕竟，您要遍历的东西提示您进行猜测。里面不需要第二层循环。想一想您何时停止提出猜测-猜测何时达到5或何时获得正确答案。那么，您什么时候想继续猜测呢？当猜测小于5并且他们没有正确时。另外，您想根据循环correct的值说出它们是否在循环结束后丢失。

while(numGuesses<5 && !correct) {
    cout << "\nGuess the number the computer randomply picked between 1 - 100: ";
    numGuesses++;
    cin >> guess;
    if(guess<number){
        cin.clear(); //clears input stream
        cin.ignore(256, '\n');
        cout << "\nSorry, your guess is too low";
    }
    else if (guess>number){
        cout << "\nSorry, your guess is too high";
    }
    else{
        cout << "\nYou guessed right, you win!";
        correct = !correct;
    }
}
if (!correct) { // loop stopped before they got it correct
    cout << "Sorry, you lost. The number is: " << number;
}

在打印语句的末尾还需要"\n"或std::endl，否则代码会将所有内容打印在一行上。

Answer 2

您不需要2个小时...

while(numGuesses < 5 && !correct)
{
       // your logic here
}

之后，您可以检查变量正确或 numGuesss 。例如：

if(!correct)
    // your code

内部while循环迭代与外部循环

2 个答案: