Question

我有一个带有json的字符串，其属性包含破折号。我想将其转换为带下划线的对象。我尝试使用Json4s库，但出现了异常。

Exception in thread "main" org.json4s.package$MappingException: No usable value for some_field
Did not find value which can be converted into java.lang.String

您能帮我为带有破折号的字段写一些自定义策略吗？

转换代码：

import org.json4s.native.JsonMethods.parse

object Converter extends App {

  case class Key(some_field: String, some_other_field: String)
  
  def jsonToObject[A](data: String)(implicit manifest: Manifest[A]): A = {
    import org.json4s.DefaultFormats
    implicit val formats = DefaultFormats
    parse(data).extract[A]
  }

  val input = "{\"some-field\":\"first\",\"some-other-field\":\"second\"}"

  val someObject = jsonToObject[Key](input)

  println(s"${someObject.some_field}  ${someObject.some_other_field}")
}

Answer 1

如果您不限于使用json4s，则可以使用jsoniter-scala轻松做到这一点：

添加依赖项：

libraryDependencies ++= Seq(
  "com.github.plokhotnyuk.jsoniter-scala" %% "jsoniter-scala-core"   % "2.6.2",
  "com.github.plokhotnyuk.jsoniter-scala" %% "jsoniter-scala-macros" % "2.6.2" % "compile-internal" // or "provided", but it is required only in compile-time
)

导出编解码器并将其用于解析：

import com.github.plokhotnyuk.jsoniter_scala.macros._
import com.github.plokhotnyuk.jsoniter_scala.core._

object Converter extends App {
  case class Key(some_field: String, some_other_field: String)

  implicit val codec: JsonValueCodec[Key] =
    JsonCodecMaker.make(CodecMakerConfig.withFieldNameMapper(JsonCodecMaker.`enforce-kebab-case`))

  val input = "{\"some-field\":\"first\",\"some-other-field\":\"second\"}"
  val someObject = readFromString(input)
  println(s"${someObject.some_field}  ${someObject.some_other_field}")
}

如何将带有短划线属性的Json转换为带有下划线字段的对象？

1 个答案: