Question

我有一定的编码背景，通常我可以解决这个问题，但是我浏览了论坛和Google并没有找到解决方案。基本上，我要从highestbars（）或lowestbars（）输出，然后将其放在close []中。对此没有快速的解决方案，因为highestbars（）/ lowestbars（）输出数据类型Series [integer]，而“ close”采用整数。

我已经尝试过使用for循环遍历相同数量的烛台并检查最高/最低价格，但这不起作用。我试图只输出最高和最低值，以将其与highest（）和lower（）进行比较，但它甚至还差得远。

由于我一直坚持下去，任何帮助将不胜感激。

//@version=4
study("Highest and Lowest Zones", overlay=true)

float high_close = close[12]
float last_close_high = high_close
int high_bar = highestbars(64)[12]

high1 = highest(64)[12]
low1 = lowest(64)[12]

for i = 0 to 64
    closeHigh = (high[i+13] > high[i+12])
    high_close := closeHigh ? close[i]: last_close_high
    last_close_high := high_close

p1 = plot(high1, title="High", color=color.red)
p2 = plot(high_close, title="Low", color=color.red)
fill(p1, p2)

float low_close = close[12]
float last_close_low = low_close

for i = 0 to 64
    closeLow = (low[i+13] > low[i+12])
    low_close := closeLow ? close[i+13]: last_close_low
    last_close_low := low_close

p3 = plot(low1, title="High", color=color.green)
p4 = plot(low_close, title="Low", color=color.green)
fill(p3, p4)

Answer 1

这对我有用：

plot(close[0-highestbars(10)])

如何获得最高/最低蜡烛的收盘价？

1 个答案: