即使鼠标被限制在200、200之类的位置,我也必须能够跟踪鼠标并将其显示在pygame窗口中。我的代码就是这个
import pygame
import time
from pygame.locals import *
import pyautogui
pygame.init()
DISPLAY=pygame.display.set_mode((int(2560/3),int(1440/3)),0,32)
WHITE=(255,255,255)
BLUE=(0,0,255)
DISPLAY.fill(WHITE)
w = pyautogui.position()
x_mouse = w.x
y_mouse = w.y
oldx = x_mouse
oldy = y_mouse
div = 3
x = x_mouse/div
y = y_mouse/div
while True:
DISPLAY.fill(WHITE)
pygame.draw.rect(DISPLAY,BLUE,(x,y,50,50))
w = pyautogui.position()
x_mouse = w.x
y_mouse = w.y
if x_mouse > oldx:
x+=(x_mouse-oldx)/div
if x_mouse < oldx:
x-=(oldx-x_mouse)/div
if y_mouse > oldy:
y+=(y_mouse-oldy)/div
if y_mouse < oldy:
y-=(oldy-y_mouse)/div
oldx = x_mouse
oldy = y_mouse
for event in pygame.event.get():
if event.type==QUIT:
pygame.quit()
pygame.display.update()
这可以正常工作,但是当鼠标被限制在某个位置时,它可以完全解决问题,以任何方式解决此问题?
答案 0 :(得分:0)
我建议使用 pygame.mouse
模块和 pygame.mouse.get_pos()
而不是 pyautogui 而不是:
import pygame
from pygame.locals import *
pygame.init()
DISPLAY = pygame.display.set_mode((int(2560/3),int(1440/3)),0,32)
clock = pygame.time.Clock()
WHITE = (255, 255, 255)
BLUE = (0, 0, 255)
x_mouse, y_mouse = pygame.mouse.get_pos()
div = 10
x, y = x_mouse/div, y_mouse/div
while True:
clock.tick(60)
for event in pygame.event.get():
if event.type==QUIT:
pygame.quit()
x_mouse, y_mouse = pygame.mouse.get_pos()
x += (x_mouse - x) / div
y += (y_mouse - y) / div
DISPLAY.fill(WHITE)
rect = pygame.Rect(0, 0, 50, 50)
rect.center = round(x), round(y)
pygame.draw.rect(DISPLAY, BLUE, rect)
pygame.display.update()