Question

如果变量值在j = <10之间，则分页显示错误“对不起，用户已经...” 然后我尝试为变量k分配另一个随机值，然后再次填写表格。

仅当出现错误时，我才想执行driver.findElement(By.xpath("//*[contains(text(),'Sorry ! ')]")).isDisplayed()步骤。否则，仅打印成功消息。

即使我收到成功消息，这里的问题仍然是由于driver.findElement(By.xpath("//*[contains(text(),'Sorry ! ')]")).isDisplayed()而导致找不到元素错误。我也尝试实现boolean Sorry_Error = driver.findElement(By.xpath("//*[contains(text(),'Sorry ! ')]")).isDisplayed();，但我认为这是相似的逻辑，只是实现方式不同。如果没有错误，则循环应继续执行else块，但将其插入.isDisplayed xpath并抛出错误。处理用户已经存在的错误不是正确的方法，还是有其他逻辑？

This is success message

This is error message

package com.self.learn;

import java.util.Random;
import java.util.concurrent.TimeUnit;

import org.openqa.selenium.By;
import org.openqa.selenium.JavascriptExecutor;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.chrome.ChromeDriver;
import org.openqa.selenium.support.ui.ExpectedConditions;
import org.openqa.selenium.support.ui.WebDriverWait;
import org.testng.annotations.Test;

public class testandquiz {

    public static WebDriverWait wait;

    @Test
    public void Simple_Test() throws InterruptedException {

        System.setProperty("webdriver.chrome.silentOutput", "true");
        System.setProperty("webdriver.chrome.driver", "src/main/resources/chromedriver.exe");
        WebDriver driver = new ChromeDriver();
        wait = new WebDriverWait(driver, 10);
        driver.manage().deleteAllCookies();

        driver.get("https://www.testandquiz.com/user-registration");
        driver.manage().window().maximize();
        driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
        ((JavascriptExecutor) driver).executeScript("scroll(0,300)");

        WebElement Fname = driver.findElement(By.id("first_name"));
        WebElement Lname = driver.findElement(By.id("last_name"));
        WebElement User_name = driver.findElement(By.id("user_name"));
        WebElement email_address = driver.findElement(By.id("email_address"));
        WebElement password = driver.findElement(By.id("password"));
        WebElement re_password = driver.findElement(By.id("re_password"));
        WebElement city = driver.findElement(By.id("city"));
        WebElement state = driver.findElement(By.id("state"));
        WebElement country = driver.findElement(By.id("country"));
        WebElement pin_code = driver.findElement(By.id("pin_code"));
        WebElement contact_no = driver.findElement(By.id("contact_no"));

        Random randomGenerator = new Random();
        int j = 10;
        int k = 99999;
        int i = randomGenerator.nextInt(j);

        Fname.sendKeys("Test" + i + "");
        Lname.sendKeys("Test" + i + "");
        User_name.sendKeys("Test" + i + "");
        email_address.sendKeys("Test" + i + "");
        password.sendKeys("Test" + i + "");
        re_password.sendKeys("Test" + i + "");
        city.sendKeys("Test" + i + "");
        state.sendKeys("Test" + i + "");
        country.sendKeys("Test" + i + "");
        pin_code.sendKeys("Test" + i + "");
        contact_no.sendKeys("1234567890");

        driver.findElement(By.xpath("//button[contains(text(),'Sign Up')]")).click();

        if (driver.findElement(By.xpath("//*[contains(text(),'Sorry ! ')]")).isDisplayed()) {

            WebElement Fname1 = driver.findElement(By.id("first_name"));
            WebElement Lname1 = driver.findElement(By.id("last_name"));
            WebElement User_name1 = driver.findElement(By.id("user_name"));
            WebElement email_address1 = driver.findElement(By.id("email_address"));
            WebElement password1 = driver.findElement(By.id("password"));
            WebElement re_password1 = driver.findElement(By.id("re_password"));
            WebElement city1 = driver.findElement(By.id("city"));
            WebElement state1 = driver.findElement(By.id("state"));
            WebElement country1 = driver.findElement(By.id("country"));
            WebElement pin_code1 = driver.findElement(By.id("pin_code"));
            WebElement contact_no1 = driver.findElement(By.id("contact_no"));

            Fname1.clear();
            Fname1.sendKeys("Test" + k + "");
            Lname1.clear();
            Lname1.sendKeys("Test" + k + "");
            User_name1.clear();
            User_name1.sendKeys("Test" + k + "");
            email_address1.clear();
            email_address1.sendKeys("Test" + k + "");
            password1.clear();
            password1.sendKeys("Test" + k + "");
            re_password1.clear();
            re_password1.sendKeys("Test" + k + "");
            city1.clear();
            city1.sendKeys("Test" + k + "");
            state1.clear();
            state1.sendKeys("Test" + k + "");
            country1.clear();
            country1.sendKeys("Test" + k + "");
            pin_code1.clear();
            pin_code1.sendKeys("Test" + k + "");
            contact_no1.clear();
            contact_no1.sendKeys("1234567890");

            driver.findElement(By.xpath("//button[contains(text(),'Sign Up')]")).click();
        }

        else {

            String Message = driver.findElement(By.xpath("//div[contains(text(),'verification mail')]")).getText();
            System.out.println(Message);
        }

    }
}

我不知道如何实现这种逻辑。

Answer 1

您在这里不一定需要等待...取决于JavaScript是否更新DOM。如果是在标准页面加载之后，则只需使用：

   List<WebElement> elements = driver.findElements(By.xpath("//*[contains(text(), 'Sorry')]");
        if (elements.size() > 0)
            {
            // sorry found
            }
            else
            {
            // sorry not found
            }

否则请尝试使用try / catch：

 try {
         WebDriverWait wait = new WebDriverWait(driver, 5);
         WebElement element =  wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//*[contains(text(), 'Sorry')]"));     
            // sorry found             
         }
         catch (Exception ex)
         {
         //sorry not found
         }

对错误文本使用相同的逻辑。

如何在Java Selenium中使用if-else循环解决此问题？

1 个答案: