public static void addALLToXML(Collection<Server> svr) throws IOException,
ParserConfigurationException, TransformerException
{
DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory
.newInstance();
DocumentBuilder documentBuilder = documentBuilderFactory
.newDocumentBuilder();
Document document = documentBuilder.newDocument();
// Root Element
Element rootElement = document.createElement("Servers");
document.appendChild(rootElement);
for (Server i : svr)
{
// server elements
Element server = document.createElement("server");
rootElement.appendChild(server);
Element name = document.createElement("name");
name.appendChild(document.createTextNode(i.getName()));
server.appendChild(name);
Element port = document.createElement("port");
port.appendChild(document.createTextNode(Integer.toString(i.getPort())));
server.appendChild(port);
}
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
DOMSource source = new DOMSource(document);
StreamResult result = new StreamResult("/home/user/server.xml");
transformer.transform(source, result);
}
这是我需要帮助的功能:
public static void addNodeToXML(String nameIn, String portIn)
throws ParserConfigurationException, SAXException, IOException
{
DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory
.newInstance();
DocumentBuilder documentBuilder = documentBuilderFactory
.newDocumentBuilder();
/* parse existing file to DOM */
Document document = documentBuilder
.parse(new File("/home/user/server.xml"));
// Root Element
Element rootElement = document.createElement("Servers");
document.appendChild(rootElement);
// server elements
Element server = document.createElement("server");
rootElement.appendChild(server);
Element name = document.createElement("name");
name.appendChild(document.createTextNode(nameIn));
server.appendChild(name);
Element port = document.createElement("port");
port.appendChild(document.createTextNode(portIn));
server.appendChild(port);
}
原件:
<Servers>
<server>
<name>something</name>
<port>port</port>
</server>
</Servers>
通缉:
<Servers>
<server>
<name>something</name>
<port>port</port>
</server>
<server>
<name>something</name>
<port>port</port>
</server>
<Servers>
答案 0 :(得分:34)
以下完整示例将从当前目录中读取现有 server.xml
文件,附加新服务器并将文件重新写入server.xml
。如果没有现有的.xml文件,它就无法运行,因此您需要修改代码来处理这种情况。
import java.util.*;
import javax.xml.transform.*;
import javax.xml.transform.stream.*;
import javax.xml.transform.dom.*;
import org.w3c.dom.*;
import javax.xml.parsers.*;
public class AddXmlNode {
public static void main(String[] args) throws Exception {
DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder documentBuilder = documentBuilderFactory.newDocumentBuilder();
Document document = documentBuilder.parse("server.xml");
Element root = document.getDocumentElement();
Collection<Server> servers = new ArrayList<Server>();
servers.add(new Server());
for (Server server : servers) {
// server elements
Element newServer = document.createElement("server");
Element name = document.createElement("name");
name.appendChild(document.createTextNode(server.getName()));
newServer.appendChild(name);
Element port = document.createElement("port");
port.appendChild(document.createTextNode(Integer.toString(server.getPort())));
newServer.appendChild(port);
root.appendChild(newServer);
}
DOMSource source = new DOMSource(document);
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
StreamResult result = new StreamResult("server.xml");
transformer.transform(source, result);
}
public static class Server {
public String getName() { return "foo"; }
public Integer getPort() { return 12345; }
}
}
示例 server.xml 文件:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Servers>
<server>
<name>something</name>
<port>port</port>
</server>
</Servers>
代码的主要更改是而不是创建新的“root”元素。上面的示例只使用现有server.xml
中的当前根节点,然后只需附加一个新的 Server 元素并重写该文件。
答案 1 :(得分:6)
要附加新数据元素,只需执行此操作...
Document doc = docBuilder.parse(is);
Node root=doc.getFirstChild();
Element newserver=doc.createElement("new_server");
root.appendChild(newserver);
easy ....'is'是一个InputStream对象。休息类似于你的代码....刚刚尝试过......
答案 2 :(得分:1)
您可以将现有XML文件解析为DOM,并将新元素附加到DOM。与您在创建全新XML时所做的非常相似。我假设您不必担心重复的服务器。如果你不必担心这一点,你将不得不浏览DOM中的元素来检查重复项。
DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder documentBuilder = documentBuilderFactory.newDocumentBuilder();
/* parse existing file to DOM */
Document document = documentBuilder.parse(new File("exisgint/xml/file"));
Element root = document.getDocumentElement();
for (Server newServer : Collection<Server> bunchOfNewServers){
Element server = Document.createElement("server");
/* create and setup the server node...*/
root.appendChild(server);
}
/* use whatever method to output DOM to XML (for example, using transformer like you did).*/
答案 3 :(得分:0)
如果需要在某个特定位置插入节点/元素,可以执行后续步骤
这是一个简单的算法,但应该有效...
答案 4 :(得分:-1)
你可以使用DOM4j来做这件事。