我使用FragmentPagerAdapter。当我从itemList中删除项目并notifyDataSetChanged.Fragments重新加载。在这种情况下,我正在丢失其他片段中的数据。如何在不丢失其他片段中数据的情况下实现这一目标
public class BasicViewPagerAdapter extends FragmentPagerAdapter {
private final List<Fragment> mFragments;
public BasicViewPagerAdapter(FragmentManager fm, List<Fragment> fragments) {
super(fm);
this.mFragments = fragments;
}
@Override
public Fragment getItem(int i) {
return mFragments.get(i);
}
@Override
public int getCount() {
return mFragments.size();
}
public void remove(int cashBoxPosition) {
mFragments.remove(cashBoxPosition);
notifyDataSetChanged();
}
}
fragmentList.remove(event.getCashBoxPosition()); mAdapterViewPager.remove(event.getCashBoxPosition());
答案 0 :(得分:0)
通过onSaveInstanceState/onViewStateRestored
在要保存数据的片段中保存并恢复状态,这是唯一的方法
答案 1 :(得分:0)
最后使用viewpager2解决了
public class BasicViewPager2Adapter extends FragmentStateAdapter {
private List<Fragment> mFragments;
public BasicViewPager2Adapter(FragmentActivity fa, List<Fragment> fragments) {
super(fa);
this.mFragments = fragments;
}
@NonNull
@Override
public Fragment createFragment(int i) {
return mFragments.get(i);
}
@Override
public int getItemCount() {
return mFragments.size();
}
@Override
public long getItemId(int position) {
return mFragments.get(position).hashCode();
}
@Override
public boolean containsItem(long itemId) {
return super.containsItem(itemId);
}
public void remove(int cashBoxPosition) {
mFragments.remove(cashBoxPosition);
notifyDataSetChanged();
}
}