我有一个像这样的数据框test
:
dput(test)
structure(list(X = 1L, entityId = structure(1L, .Label = "HOST-123", class = "factor"),
displayName = structure(1L, .Label = "server1", class = "factor"),
discoveredName = structure(1L, .Label = "server1", class = "factor"),
firstSeenTimestamp = 1593860000000, lastSeenTimestamp = 1603210000000,
tags = structure(1L, .Label = "c(\"CONTEXTLESS\", \"CONTEXTLESS\", \"CONTEXTLESS\", \"CONTEXTLESS\", \"CONTEXTLESS\", \"CONTEXTLESS\", \"CONTEXTLESS\", \"CONTEXTLESS\"), c(\"app1\", \"client\", \"org\", \"app1\", \"DATA_CENTER\", \"PURPOSE\", \"REGION\", \"Test\"), c(NA, \"NONE\", \"Host:Environment:test123\", \"111\", \"222\", \"GENERAL\", \"444\", \"555\")", class = "factor")), .Names = c("X",
"entityId", "displayName", "discoveredName", "firstSeenTimestamp",
"lastSeenTimestamp", "tags"), class = "data.frame", row.names = c(NA,
-1L))
有一列称为tags
的列应成为数据框。我需要摆脱标记中的第一行(它一直说:CONTEXTLESS,在标记中扩展第二列(使它们成为列。最后,我需要在每个扩展列下的标记中插入第三列值。
例如in需要看起来像这样:
structure(list(entityId = structure(1L, .Label = "HOST-123", class = "factor"),
displayName = structure(1L, .Label = "server1", class = "factor"),
discoveredName = structure(1L, .Label = "server1", class = "factor"),
firstSeenTimestamp = 1593860000000, lastSeenTimestamp = 1603210000000,
app1 = NA, client = structure(1L, .Label = "None", class = "factor"),
org = structure(1L, .Label = "Host:Environment:test123", class = "factor"),
app1.1 = 111L, data_center = 222L, purppose = structure(1L, .Label = "general", class = "factor"),
region = 444L, test = 555L), .Names = c("entityId", "displayName",
"discoveredName", "firstSeenTimestamp", "lastSeenTimestamp",
"app1", "client", "org", "app1.1", "data_center", "purppose",
"region", "test"), class = "data.frame", row.names = c(NA, -1L
))
我需要删除一直说“ contextless”的第一个向量,将第二个向量添加到列中。每个第二矢量值应为列名。最后一个向量应该是新添加的列的值。
答案 0 :(得分:1)
如果您愿意丢弃第一个“行”的垃圾,然后仔细分析解析的副作用,那么这可能是一个不错的起点:
read.table(text=gsub("\\),", ")\n", test$tags[1]), sep=",", skip=1, #drops line
header=TRUE)
c.app1 client org app1 DATA_CENTER PURPOSE REGION Test.
1 c(NA NONE Host:Environment:test123 111 222 GENERAL 444 555)
read.table
函数使用scan
函数,该函数不知道“ c(”和“)”是有意义的。另一种选择是在第二行和第三行尝试eval(parse(text= .))
(它将知道它们包含向量),但是我看不到一种干净的方法。最初,我尝试使用strsplit分隔行,但这导致我松开了括号。
通过添加更多的gsub操作,在清理过程中遇到了麻烦:
read.table(text=gsub("c\\(|\\)","", # gets rid of enclosing "c(" and ")"
gsub("\\),", "\n", # inserts line breaks
test$tags[1])),
sep=",", #lets commas be parsed
skip=1, #drops line
header=TRUE) # converts to colnames
app1 client org app1.1 DATA_CENTER PURPOSE REGION Test
1 NA NONE Host:Environment:test123 111 222 GENERAL 444 555
在app1的第二个实例中添加“ .1”的原因是,除非使用check.names=FALSE
覆盖数据帧中的R同名,否则它们必须是唯一的。
答案 1 :(得分:1)
这是一种tidyverse
方法
library(dplyr)
library(tidyr)
str2dataframe <- function(txt, keep = "all") {
# If you can confirm that all vectors are of the same length, then we can make them into columns of a data.frame
out <- eval(parse(text = paste0("data.frame(", as.character(txt),")")))
# rename columns as X1, X2, ...
nms <- make.names(seq_along(out), unique = TRUE)
if (keep == "all")
keep <- nms
`names<-`(out, nms)[, keep]
}
df %>%
mutate(
tags = lapply(tags, str2dataframe, -1L),
tags = lapply(tags, function(d) within(d, X2 <- make.unique(X2)))
) %>%
unnest(tags) %>%
pivot_wider(names_from = "X2", values_from = "X3")
df
看起来像这样
> df
X entityId displayName discoveredName firstSeenTimestamp lastSeenTimestamp
1 1 HOST-123 server1 server1 1.59386e+12 1.60321e+12
tags
1 c("CONTEXTLESS", "CONTEXTLESS", "CONTEXTLESS", "CONTEXTLESS", "CONTEXTLESS", "CONTEXTLESS", "CONTEXTLESS", "CONTEXTLESS"), c("app1", "client", "org", "app1", "DATA_CENTER", "PURPOSE", "REGION", "Test"), c(NA, "NONE", "Host:Environment:test123", "111", "222", "GENERAL", "444", "555")
输出看起来像这样
# A tibble: 1 x 14
X entityId displayName discoveredName firstSeenTimestamp lastSeenTimestamp app1 client org app1.1 DATA_CENTER PURPOSE REGION Test
<int> <fct> <fct> <fct> <dbl> <dbl> <chr> <chr> <chr> <chr> <chr> <chr> <chr> <chr>
1 1 HOST-123 server1 server1 1593860000000 1603210000000 NA NONE Host:Environment:test123 111 222 GENERAL 444 555