左连接Doctrine查询语言

时间:2011-06-22 18:21:32

标签: php mysql symfony1 doctrine

如果我没有在谷歌做足够的研究,我想道歉但是说实话我不确切知道要搜索什么。我的问题是与学说。我使用Symfony框架,我想在DQL中编写以下原始查询:

SELECT c.id AS id,
c.name AS name,
c.active AS active,
count(c2.id) AS depth,
(c.rht - c.lft) as rng
FROM (categories c
LEFT JOIN categories c2 ON ( (c2.lft < c.lft) AND (c2.rht > c.rht) AND c2.active ) )
GROUP by c.id
ORDER by c.lft ASC

我可以像原始查询一样编写它,但我需要在DQL中使用它,因为我想将它用于sfWidgetFormDoctrineChoice小部件。任何帮助都非常感谢。

提前致谢!

1 个答案:

答案 0 :(得分:3)

可能的方法是:

$query = Doctrine_Query::create()
  ->select('c.name AS name,
            c.active AS active,
            count(c2.id) AS depth,
            (c.rht - c.lft) as rng')
  ->from('categories c')
  ->leftJoin('c.Categories c2 ON ( (c2.lft < c.lft) AND (c2.rht > c.rht) AND c2.active')
  ->groupBy('c.id')
  ->orderBy('c.lft ASC');

但我认为你错了。你看看了学说的树行为吗? http://www.doctrine-project.org/documentation/manual/1_0/nl/hierarchical-data#nested-set:advanced-usage:fetching-a-tree-with-relations