我有一个2D彩色图像和一个标签图像(标签的投影)
标签图像的输出如下:
class A
{
public:
virtual void show()
{
cout << "you are in A";
}
};
class B : public A
{
public:
void show()
{
cout << "you are in B";
}
};
int main()
{
A *a[5];
A **aa[5];
B *b[5];
for (int i = 0; i < 5; i++)
{
a[i] = new A;
aa[i] = &a[i];
aa[i]->show();
b[i] = new B;
aa[i] = &b[i];
aa[i]->show();
}
return 0;
}
如何在原始2D彩色图像中的所有对象(用标签表示)周围绘制边框?
答案 0 :(得分:2)
使用NumPy的boolean array indexing和OpenCV的boundingRect函数可以轻松完成此任务。
我从here拍摄了这张照片
和此细分蒙版
遮罩是OpenCV遇到问题的索引图像,另请参见here。因此,我们还将Pillow用于此任务。
这是代码:
import cv2
import numpy as np
from PIL import Image
# Read color image
img = cv2.imread('0.jpg')
# Read mask; OpenCV can't handle indexed images, so we need Pillow here
# for that, see also: https://stackoverflow.com/q/59839709/11089932
mask = np.array(Image.open('0_mask.png'))
# Iterate all colors in mask
for color in np.unique(mask):
# Color 0 is assumed to be background or artifacts
if color == 0:
continue
# Determine bounding rectangle w.r.t. all pixels of the mask with
# the current color
x, y, w, h = cv2.boundingRect(np.uint8(mask == color))
# Draw bounding rectangle to color image
out = cv2.rectangle(img.copy(), (x, y), (x+w, y+h), (0, int(color), 0), 2)
# Show image with bounding box
cv2.imshow('img_' + str(color), out)
# Show mask
cv2.imshow('mask', mask)
cv2.waitKey(0)
cv2.destroyAllWindows()
这些是输出:
我决定输出几张图像,因为对于给定的图像,边界框严重重叠。要将所有矩形绘制到同一图像,只需将相应的rectangle
命令替换为
img = cv2.rectangle(img, (x, y), (x+w, y+h), (0, int(color), 0), 2)
----------------------------------------
System information
----------------------------------------
Platform: Windows-10-10.0.16299-SP0
Python: 3.8.5
NumPy: 1.19.2
OpenCV: 4.4.0
Pillow: 7.2.0
----------------------------------------