我如何获得rob命令以停止忽略某些代码行？

Question

我一直在尝试让！rob命令在我的discord机器人上工作一段时间，但是它总是忽略let authorBal = db.fetch(`money_${message.guild.id}_${message.author.id}`);之后和''const embed = new Discord.MessageEmbed（） .setTitle（${author.username} just robbed ${user.username} for ${random} coins!） .setDescription（Unlucky ${user.username}）;

db.add（money_${message.guild.id}_${user.id}，随机）； db.subtract（money_${message.guild.id}_${user.id}，随机）

message.channel.send（embed）```这是完整的代码请帮助

const db = require('quick.db')
const Discord = require('discord.js');

module.exports = {

name:"rob",
description:"rob someone!",

async run(client, message, args) {

let user = message.mentions.users.first();
let fine = Math.floor(Math.random() * 100) + 1;
let random = Math.floor(Math.random() * 100) + 1; 

if(!user)return message.channel.send('Please metion who you want to rob')


let author = message.author;

if(author === user) return message.channel.send('you can\'t rob yourself')


let authorBal = db.fetch(`money_${message.guild.id}_${message.author.id}`);


if(author < 100) return message.channel.send(':x: You need at least 100 coins to rob someone')


let userBal = db.fetch(`money_${message.guild.id}_${user.id}`);


if(userBal = 0 ) {
    message.channel.send('You just tried to rob a poor person! :angry:')
    db.subtract(`money_${message.guild.id}_${user.id}`, fine);
    return;
}





const embed = new Discord.MessageEmbed()
.setTitle(`${author.username} just robbed ${user.username} for ${random} coins!`)
.setDescription(`Unlucky ${user.username}`);

db.add(`money_${message.guild.id}_${user.id}`, random); 
db.subtract(`money_${message.guild.id}_${user.id}`, random)

message.channel.send(embed)
}}