Question

08-SEP-20 08:55:05
08-SEP-20 15:36:13

下面的查询对于15:36:13正常工作，因为它四舍五入到15:30，但是8:55:05在应四舍五入到09:00时四舍五入到08:45

select event_date,trunc(event_date,'mi') - numtodsinterval(  mod(to_char(event_date,'mi'),15),  'minute'  ) as nearest_quarter
from time_source_in_all where empno = '002307718' and event_date between  '8-sep-2020' and '9-sep-2020'

Answer 1

我认为这将满足您的要求

select trunc(event_date, 'HH') + round(extract(minute from event_date) / 15) * interval '15' minute )
. . .

注意：我更喜欢extract()，因为它是标准SQL。但是它假定该列是timestamp而不是date。

或等价物：

select trunc(event_date, 'HH') + numtodsinterval(round(to_number(to_char(event_date, 'MI')) / 15) * 15, 'minute')

Answer 2

您可以使用：

SELECT event_date,
       TRUNC( event_date, 'HH' )
         + ROUND( EXTRACT( MINUTE FROM CAST( event_date AS TIMESTAMP ) ) / 15 )
           * INTERVAL '15' MINUTE
         AS rounded_15_event_date
FROM   table_name

或：

SELECT event_date,
       TRUNC( event_date, 'HH' )
         + ROUND( ( event_date - TRUNC( event_date, 'HH' ) ) * 24 * 4 )
           * INTERVAL '15' MINUTE
         AS rounded_15_event_date
FROM   table_name

其中，为您的示例数据：

CREATE TABLE table_name ( event_date ) AS
SELECT DATE '2020-09-08' + INTERVAL '08:55:05' HOUR TO SECOND FROM DUAL UNION ALL
SELECT DATE '2020-09-08' + INTERVAL '15:36:13' HOUR TO SECOND FROM DUAL

两个输出：

EVENT_DATE          | ROUNDED_15_EVENT_DATE
:------------------ | :--------------------
2020-09-08 08:55:05 | 2020-09-08 09:00:00  
2020-09-08 15:36:13 | 2020-09-08 15:30:00

db <>提琴here

Oracle查询向上或向下舍入到最近的15分钟间隔

2 个答案: