Question

我有两个数组：

import numpy as np
a = np.array([[1,2,3], [4,5,6]])
b = np.array([5, 6])

当我尝试使用以下代码将b附加到a的最后一列时，将a附加到np.hstack([a, b]) it thows an error: Traceback (most recent call last): File "<stdin>", line 1, in <module> File "<__array_function__ internals>", line 6, in hstack File "C:\Users\utkal\anaconda3\envs\AIML\lib\site-packages\numpy\core\shape_base.py", line 345, in hstack return _nx.concatenate(arrs, 1) File "<__array_function__ internals>", line 6, in concatenate ValueError: all the input arrays must have same number of dimensions, but the array at index 0 has 2 dimension(s) and the array at index 1 has 1 dimension(s)

1 2 3 5
4 5 6 6

我希望最终数组为：

  var templates = DriveApp.getFilesByName('Template'); // get the files named Template (only one)
  var template = templates.next(); // get the first files in the list
  var newFile = template.makeCopy(name,newFolder); // Make a copy of the Template file and put it in NewFolder
  
  var ss = SpreadsheetApp.open(newFile);
  var sheet = ss.getSheets()[0];
  sheet.getActiveRange('B1').setValue(name);

Answer 1

您可以这样做：

np.hstack((a,b.reshape(2,1)))
array([[1, 2, 3, 5],
       [4, 5, 6, 6]])

Answer 2

np.hstack是{= 1轴上的np.concatenate的快捷方式。因此，这要求两个数组都具有相同的形状，并且所有尺寸都必须匹配，除了连接轴上。在您的情况下，既需要二维数组又需要匹配维度0

所以你需要

np.hstack([a, b[:,None]])

Out[602]:
array([[1, 2, 3, 5],
       [4, 5, 6, 6]])

或使用np.concatenate

np.concatenate([a, b[:,None]], axis=1)

Out[603]:
array([[1, 2, 3, 5],
       [4, 5, 6, 6]])

如何在python中将最后一列（1d数组）附加到2d numpy数组？

2 个答案: