我对这段代码感到沮丧。我们的目标是创建一个剪刀纸游戏，最好的3个。我试图做一个“ while”循环，但是我全都错了，最终把它报废了，回到非循环代码
如果有人能启发我如何使它循环播放，直到计算机或玩家获得3分，我将非常感激！非常感谢 抱歉，我需要澄清，它需要循环播放直到用户或计算机赢得3次胜利，因此他们重新进行战斗直到用户或计算机获得3次胜利
import java.util.Scanner;
import java.util.Random;
public class RockPaperScissors
{
public static void main(String[] args)
{
Scanner key;
Random randGen;
char userChoice, computerChoice;
int winner, compInt;
int computerScore;
int userScore;
int scoreCounter;
/***** INITIALIZATION SECTION *****/
key = new Scanner(System.in);
randGen = new Random();
userChoice = ' ';
computerChoice = ' ';
//winner = -1;
compInt = -1;
computerScore = 0;
userScore = 0;
scoreCounter = 0;
System.out.println("What is your name?");
String name = key.nextLine();
System.out.println(name + " play rock, paper, or scissors with me!!");
/***** INPUT SECTION *****/
System.out.println("Please enter R for rock, P for paper, or S for scissors:");
userChoice = key.next().toUpperCase().charAt(0);
//key.close();
/***** PROCESSING SECTION *****/
compInt=randGen.nextInt(3);
if (compInt == 0)
{
computerChoice = 'R';
}
else if (compInt == 1)
{
computerChoice = 'P';
}
else if (compInt == 2)
{
computerChoice = 'S';
}
winner = RockPaperScissors.decideWinner(userChoice,computerChoice);
/***** OUTPUT SECTION *****/
System.out.printf("Player: %c%nComputer: %c%n", userChoice, computerChoice);
switch (winner)
{
case 0:
System.out.println("It's a tie!");
System.out.println(name + ": " + userScore + ", Computer:" + computerScore );
break;
case 1:
System.out.println("You won!");
userScore++;
System.out.println(name + ": " + userScore + ", Computer:" + computerScore );
break;
case 2:
System.out.println("Computer won!");
computerScore++;
System.out.println(name + ": " + userScore + ", Computer:" + computerScore );
break;
default:
System.out.println("Invalid choice, try again.");
break;
}
//System.out.println("Thanks for playing!);
}
/***** STATIC METHODS *****/
/**Description: given two characters (R,P, or S) determines winner using rock
* paper rules. Assume input is valid and error checking is done in main
* programme. **/
public static int decideWinner(char p1,char p2)
{
String combo;
combo = String.format("%c%c", p1, p2);
switch(combo)
{
case "RS":
case "PR":
case "SP":
return 1;
case "RP":
case "PS":
case "SR":
return 2;
case "RR":
case "PP":
case "SS":
return 0;
}
return -1;
}
}
/***************************************************
while(userScore == 3)
{
System.out.println("You won the game" +name+ "! Congratulations");
scoreCounter++;
}
while(computerScore == 3)
{
System.out.println("Sorry " +name+ ", Computer won...");
scoreCounter++;
}
**************************************************/
答案 0 :(得分：2)
尝试将代码拆分为每个都有各自任务的方法，这样您就可以更轻松地布局和控制程序的行为。例如。在用户输入的情况下，可以在无效输入的情况下递归地调用该方法。 对于while循环，我只是添加了一个计数器，该计数器在每局游戏结束后都会增加，直到3。
import java.util.Scanner;
import java.util.Random;
public class RockPaperScissors
{
private static int totalGames = 0;
public static void main(String[] args)
{
Scanner key;
Random randGen;
char userChoice, computerChoice;
int winner;
int computerScore;
int userScore;
/***** INITIALIZATION SECTION *****/
key = new Scanner(System.in);
randGen = new Random();
computerChoice = ' ';
//winner = -1;
computerScore = 0;
userScore = 0;
System.out.println("What is your name?");
String name = key.nextLine();
System.out.println(name + " play rock, paper, or scissors with me!!");
while(totalGames < 3) {
userChoice = getUserChoice(key, false);
/* PROCESSING SECTION */
computerChoice = getComputerChoice(computerChoice, randGen.nextInt(3));
winner = RockPaperScissors.decideWinner(userChoice, computerChoice);
totalGames++;
/* OUTPUT SECTION */
System.out.printf("Player: %c%nComputer: %c%n", userChoice, computerChoice);
switch (winner) {
case 0:
System.out.println("It's a tie!");
System.out.println(name + ": " + userScore + ", Computer:" + computerScore);
break;
case 1:
System.out.println("You won!");
userScore++;
System.out.println(name + ": " + userScore + ", Computer:" + computerScore);
break;
case 2:
System.out.println("Computer won!");
computerScore++;
System.out.println(name + ": " + userScore + ", Computer:" + computerScore);
break;
default:
System.out.println("Invalid choice, try again.");
break;
}
}
//System.out.println("Thanks for playing!);
}
private static char getComputerChoice(char computerChoice, int compInt) {
if (compInt == 0)
{
computerChoice = 'R';
}
else if (compInt == 1)
{
computerChoice = 'P';
}
else if (compInt == 2)
{
computerChoice = 'S';
}
return computerChoice;
}
private static char getUserChoice(Scanner key, boolean retry) {
char userChoice;
/* INPUT SECTION */
if(retry)
System.out.println("You entered an invalid input, please try again...");
System.out.println("Please enter R for rock, P for paper, or S for scissors:");
try {
userChoice = key.next().toUpperCase().charAt(0);
if(userChoice != 'R' && userChoice != 'P' && userChoice != 'S')
return getUserChoice(key, true);
} catch (Exception e){
return getUserChoice(key, true);
}
return userChoice;
}
/***** STATIC METHODS *****/
/**Description: given two characters (R,P, or S) determines winner using rock
* paper rules. Assume input is valid and error checking is done in main
* programme. **/
public static int decideWinner(char p1,char p2)
{
String combo;
combo = String.format("%c%c", p1, p2);
switch(combo)
{
case "RS":
case "PR":
case "SP":
return 1;
case "RP":
case "PS":
case "SR":
return 2;
case "RR":
case "PP":
case "SS":
return 0;
}
return -1;
}
}
/***************************************************
while(userScore == 3)
{
System.out.println("You won the game" +name+ "! Congratulations");
scoreCounter++;
}
while(computerScore == 3)
{
System.out.println("Sorry " +name+ ", Computer won...");
scoreCounter++;
}
**************************************************/