猫鼬查询返回匹配结果数组

Question

在以下集合中，我们希望获取所有“ approved”字段值为false的团队。如果查询工作正常，我们应该得到2个对象。

    {
        "categories": [],
        "round": 0,
        "questionNumber": 0,
        "roundStarted": false,
        "roomOpened": false,
        "gameEnded": false,
        "_id": "5f898e467405e4051439e0c1",
        "roomCode": 1234,
        "teams": [
            {
                "score": 0,
                "approved": false,
                "answerCorrect": false,
                "_id": "5f898e467405e4051439e0c2",
                "name": "Alex"
            },
            {
                "score": 0,
                "approved": false,
                "answerCorrect": false,
                "_id": "5f898e467405e4051439e0c3",
                "name": "Ritse"
            },
            {
                "score": 0,
                "approved": true,
                "answerCorrect": false,
                "_id": "5f898e467405e4051439e0c4",
                "name": "Fritz"
            }
        ]
    }

我们已经尝试了以下方法，但是我们仍然获得了所有真实的结果。

const result = await Room.find({ $and: [{ roomCode: { $eq: req.params.id } }, 
{ 'teams.approved': false } ] }, {teams: 1}) 

查询结果：

[
    {
        "_id": "5f898e467405e4051439e0c1",
        "teams": [
            {
                "score": 0,
                "approved": false,
                "answerCorrect": false,
                "_id": "5f898e467405e4051439e0c2",
                "name": "Alex"
            },
            {
                "score": 0,
                "approved": false,
                "answerCorrect": false,
                "_id": "5f898e467405e4051439e0c3",
                "name": "Ritse"
            },
            {
                "score": 0,
                "approved": true,
                "answerCorrect": false,
                "_id": "5f898e467405e4051439e0c4",
                "name": "Fritz"
            }
        ]
    }
]

我如何确保只得到前两个对象？