Question

我把这句话作为输入：

abcd 01234 87 01235

接下来，我必须检查每个单词，看它的字符是否连续。输出如下：

abcd 01234

好吧，01235包含连续的字符，但整个字也包含非连续的字符（35），所以它不会打印在屏幕上。

到目前为止，我写了这个：

function string_to_ascii($string)
{
    $ascii = NULL;

    for ($i = 0; $i < strlen($string); $i++)
    {
        $ascii[] =  ord($string[$i]);
    }

    return($ascii);
}


$input = "abcd 01234 87 01235";
//first, we split the sentence into separate words
$input = explode(" ",$input);
foreach($input as $original_word)
{
    //we need it clear
    unset($current_word);

    //convert current word into array of ascii chars
    $ascii_array = string_to_ascii($original_word);

    //needed for counting how many chars are already processed
    $i = 0;

    //we also need to count the total number chars in array
    $ascii_count = count($ascii_array);

     //here we go, checking each character from array
     foreach ($ascii_array as $char)
     {
        //if IT'S THE LAST WORD'S CHAR
        if($i+1 == $ascii_count)
        {
            //IF THE WORD HAS JUST 1 CHAR, output it
            if($ascii_count == 1)
            {
                $current_word  .= chr($char);
            }
            //IF THE WORDS HAS MORE THAN 1 CHAR
            else
            {
                //IF PREVIOUS CHAR CODE IS (CURRENT_CHAR-1)  (CONSECUTIVE, OUTPUT IT)
                if(($char - 1) == $ascii_array[($i-1)])
                {
                    $current_word .=chr($char);
                }

            }
        }
        //IF WE AREN'T YET AT THE ENDING
        else
        {
            //IF NEXT CHAR CODE IS (CURRENT_CHAR+1) (CONSECUTIVE, OUTPUT IT)
            if(($char + 1) == ($ascii_array[($i+1)]))
            {
                $current_word .=chr($char);
            }

        }

        $i++;
     }

    //FINALLY, WE CHECK IF THE TOTAL NUMBER OF CONSECUTIVE CHARS is the same as THE NUMBER OF CHARS
    if(strlen($current_word) == strlen($original_word))
    {
        $output[] = $current_word;
    }

}
//FORMAT IT BACK AS SENTENCE
print(implode(' ',$output));

但也许有另一种方法可以做到这一点，更简单？

抱歉拼写错误

Answer 1

这有效......

$str = 'abcd 01234 87 01235';

$words = explode(' ', $str);

foreach($words as $key => $word) {
    if ($word != implode(range($word[0], chr(ord($word[0]) + strlen($word) - 1)))) {
       unset($words[$key]);
    }
}

echo implode(' ', $words);

CodePad

基本上，它抓取每个单词的第一个字符，并创建字符范围，如果单词由连续字符组成，则为的值。

然后进行简单的字符串比较。

对于性能更高的版本......

$str = 'abcd 01234 87 01235'; $words = explode(' ', $str); foreach($words as $key => $word) { foreach(str_split($word) as $index => $char) { $thisOrd = ord($char); if ($index > 0 AND $thisOrd !== $lastOrd + 1) { unset($words[$key]); break; } $lastOrd = $thisOrd; } } echo implode(' ', $words);

CodePad

这两个例子都依赖于连续字符的顺序字符。这是ASCII的情况，但我不确定其他字符。

检查单词是否由连续字母字符组成

1 个答案: