如何使用square.c
循环以平方根倒数输入数字?
例如,如果我运行代码并将第一个数字设为8,它将得到8..7..6 ..的平方根,依此类推。
到目前为止,我的代码如下;现在,我只得到第一个数字的平方根:
while
答案 0 :(得分:2)
这应该做您想要的:
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
System.out.print("Enter a positive integer: ");
int start = scnr.nextInt();
if (start < 0) {
System.out.print("Error, enter a positive integer");
} else {
while (start !=0) {
double sqrt = Math.sqrt(start);
System.out.printf("%d: %,4f\n", start, sqrt);
start--;
}
}
}
输出
Enter a positive integer: 36
36: 6.000000
35: 5.916080
34: 5.830952
33: 5.744563
32: 5.656854
31: 5.567764
30: 5.477226
29: 5.385165
28: 5.291503
27: 5.196152
26: 5.099020
25: 5.000000
24: 4.898979
23: 4.795832
22: 4.690416
21: 4.582576
20: 4.472136
19: 4.358899
18: 4.242641
17: 4.123106
16: 4.000000
15: 3.872983
14: 3.741657
13: 3.605551
12: 3.464102
11: 3.316625
10: 3.162278
9: 3.000000
8: 2.828427
7: 2.645751
6: 2.449490
5: 2.236068
4: 2.000000
3: 1.732051
2: 1.414214
1: 1.000000
答案 1 :(得分:1)
如果您想实现为while循环
int i = start;
while(i >= 0){
//your variable i is decrementing not start, so Math.sqrt(i)
double sqrt = Math.sqrt(i);
System.out.println(sqrt);
i--;
}
答案 2 :(得分:0)
这里有一个针对ya的解决方案,我也修复了缩进。您的if语句后有分号,使之无用。我按照您的要求实现了while循环,该循环将显示数字,然后显示其平方根,每次迭代减少1。让我知道它是如何工作的。
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int start;
System.out.print("Enter a positive integer: ");
start = scnr.nextInt();
if (start < 0) {
System.out.print("Error, enter a positive integer");
}
while (start > 0) {
double sqrt = Math.sqrt(start);
System.out.println(start + " - " + sqrt);
start--;
}
}