Question

我已经看到了很多这方面的答案，但我似乎无法开始工作。我想我在变量类型之间感到困惑。我有一个来自NetworkStream的输入，它将一个十六进制代码放入一个String ^中。我需要接受这个字符串的一部分，将其转换为数字（可能是int），这样我就可以添加一些arithemetic，然后在表单上输出reult。我到目前为止的代码：

String^ msg; // gets filled later, e.g. with "A55A6B0550000000FFFBDE0030C8"
String^ test;

//I have selected the relevant part of the string, e.g. 5A
test = msg->Substring(2, 2);

//I have tried many different routes to extract the numverical value of the
//substring. Below are some of them:

std::stringstream ss;
hexInt = 0;
//Works if test is string, not String^ but then I can't output it later.
ss << sscanf(test.c_str(), "%x", &hexInt);

//--------
sprintf(&hexInt, "%d", test);

//--------
//And a few others that I've deleted after they don't work at all.

//Output:
this->textBox1->AppendText("Display numerical value after a bit of math");

对此的任何帮助将不胜感激克里斯

Answer 1

这有帮助吗？

String^ hex = L"5A";
int converted = System::Convert::ToInt32(hex, 16);

转换静态方法的documentation位于MSDN上。

您需要停止考虑将标准C ++库与托管类型一起使用。 .Net BCL非常好......

Answer 2

希望这会有所帮助：

/*
the method demonstrates converting hexadecimal values,
which are broken into low and high bytes.
*/
int main(){ 
//character buffer
char buf[1];
buf[0]= 0x06; //buffer initialized to some hex value
buf[1]= 0xAE; //buffer initialized to some hex value
int number=0;  

//number generated by binary shift of high byte and its OR with low byte
number = 0xFFFF&((buf[1]<<8)|buf[0]);

printf("%x",number);              //this prints AE06
printf(“%d”,number);              //this prints the integer equivalent

getch();
}

将hex转换为int

2 个答案: