我有一个场景,当使用SIGABRT杀死父进程时,会杀死生成的子进程。据我了解,孩子应该继续奔跑。为了模拟实际代码,我创建了两个文件,分别显示了子代和父代。父级写入管道,子级从读取端读取(STDIN_FILENO)。
父代码-> parent.cpp
#include <iostream>
#include <stdlib.h>
#include <string>
#include <unistd.h>
int main() {
int pipefd[2];
std::string message = "test\n";
if (pipe(pipefd) == -1) {
perror("pipe");
exit(EXIT_FAILURE);
}
int pid = fork();
if (0 == pid) {
std::cout << "Inside child process\n";
close(pipefd[1]);
char *args[] = {"./CHILD", NULL};
char *envp[] = {NULL};
if (dup2(pipefd[0], STDIN_FILENO) == -1) {
std::cout << "dup2 failed\n";
}
close(pipefd[0]);
close(pipefd[1]);
execve(args[0], args, envp);
} else {
close(pipefd[0]);
while (1) {
sleep(1);
std::cout << "parent writing -> " << message;
write(pipefd[1], message.c_str(), message.length());
}
}
return 0;
}
子代码-> child.cpp
#include <iostream>
#include <string>
#include <unistd.h>
int main() {
std::string str;
char buf;
std::cout << "[child] started\n";
while (read(STDIN_FILENO, &buf, sizeof(buf)) > 0) {
if (buf != '\n')
str += buf;
else {
write(STDOUT_FILENO, str.c_str(), str.length());
str.clear();
write(STDOUT_FILENO, "\n", 1);
}
}
std::cout << "[child] Exiting the application\n";
return 0;
}
如果父母被SIGABRT杀死,孩子也将收到同样的信息。删除管道代码后,信号不会传播。
能否请您提供一些见解?