Question

在旨在遍历每个可用符号并记录可用信息的脚本中：

int i, j, file_handle;
string InpDirectoryName, InpFileName, Textwrite, mySymbol;
//+------------------------------------------------------------------+
//| Script program start function                                    |
//+------------------------------------------------------------------+
void OnStart()
  {
//---
int MIIds[29]; // 0-28 market information type IDs
int ST;
MIIds[0] = 1;
MIIds[1] = 2;
MIIds[2] = 5;
for(i=3;i<=28; i++)
    MIIds[i] = i+6;
ST = SymbolsTotal(false);
InpDirectoryName = "";
InpFileName = "Test.csv";
Textwrite = "";
file_handle=FileOpen(InpDirectoryName+InpFileName,FILE_READ|FILE_WRITE|FILE_CSV); 
if(file_handle!=INVALID_HANDLE) 
   {
   for(i=1;i<=ST; i++)
      Print(i);

到目前为止，一切顺利，我得到了打印的“符号”列表位置的列表。但是，在尝试调用相应的SymbolName（）时，

    mySymbol = SymbolName(i, false);

下一行没有进一步的打印输出：

    Print(mySymbol);

输出如下：

0   12:29:56.630    Script test EURUSD,H4: loaded successfully
0   12:29:56.667    test EURUSD,H4: initialized
0   12:29:56.669    test EURUSD,H4: 1
...
0   12:29:56.670    test EURUSD,H4: 68
0   12:29:56.670    test EURUSD,H4: 
0   12:29:56.670    test EURUSD,H4: uninit reason 0
0   12:29:56.676    Script test EURUSD,H4: removed

如您所见，没有错误代码，在未初始化之前只有一行空输出... 为了完整起见，这是其余的代码，尽管目前尚无争议：

    SymbolSelect(mySymbol,true);
    Textwrite = mySymbol;
    for(j=0;i<=28; j++)
        Textwrite = Textwrite + "," + MarketInfo(mySymbol,j);
    FileWrite(file_handle,Textwrite);
   FileClose(file_handle);
   }
else Print("Operation FileOpen failed, error ",GetLastError()); 
  }

感谢任何感想

为什么SymbolName（）不返回任何内容？

0 个答案: