Question

在我的应用程序中，我有一个弹出控制器，当从其他视图点击时显示一堆图像。另一个视图中有一些图像。所有图像上方都有一个箭头按钮，点击弹出结果获取我转到了问题。例如，我点击了第二张图片上方的箭头按钮并弹出显示。现在当我从弹出窗口中选择任何图像时，我想将该图像设置为图像视图主视图（或由箭头按钮组成的图像视图）。但我得到的是，当我从弹出窗口中选择任何图像时，它总是被设置为主视图中出现的最后一个图像视图。我想设置它位于上方相同的图像视图上，其中单击了箭头按钮以显示弹出窗口。

我的代码是： -

主要观点： -

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {    
    UITableViewCell *cell = nil;

    static NSString *AutoCompleteRowIdentifier = @"AutoCompleteRowIdentifier";

    cell = [tableView dequeueReusableCellWithIdentifier:AutoCompleteRowIdentifier];
    if (cell == nil) {
        cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:AutoCompleteRowIdentifier] autorelease];

        UIImageView * imageView1 = [[[UIImageView alloc] initWithFrame:CGRectMake(25, 4, 80, 80)] autorelease];
        UIImageView * imageView2 = [[[UIImageView alloc] initWithFrame:CGRectMake(115,4,80, 80)] autorelease];
        UIImageView * imageView3 = [[[UIImageView alloc] initWithFrame:CGRectMake(205,4, 80, 80)] autorelease];
        UIImageView * imageView4 = [[[UIImageView alloc] initWithFrame:CGRectMake(295,4, 80, 80)] autorelease];

        imageView1.tag = j;
        imageView2.tag = j+1;
        imageView3.tag = j+2;
        imageView4.tag = j+3;

        [cell.contentView addSubview:imageView1];
        [cell.contentView addSubview:imageView2];
        [cell.contentView addSubview:imageView3];
        [cell.contentView addSubview:imageView4];   
    }

    for ( int i = 1; i <= j; i++ ) {
        imageView = (UIImageView *)[cell.contentView viewWithTag:i];
        imageView.image=nill
    }

    int photosInRow;

    if ( (indexPath.row < [tableView numberOfRowsInSection:indexPath.section] - 1) || ([sentence count] % 4 == 0) ) {
        photosInRow = 4;
    } else {
        photosInRow = [sentence count] % 4;
    }

    for ( int i = 1; i <=[sentence count]; i++ ){
        imageView = (UIImageView *)[cell.contentView viewWithTag:i];

        [self setImage1:imageView];
    }

    return cell;
}

点击按钮的事件： -

-(void)showPopOver:(id)sender
{
    ModalView *mvc = [[ModalView alloc]init];

    [mvc settingParentButton:imageView];
    [mvc settingPop:detailViewPopover]; 

    // Present the popover from the button that was tapped in the detail view.
    [detailViewPopover presentPopoverFromRect:CGRectMake(0,0, 325, 650) inView:self.view permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];

    // Set the last button tapped to the current button that was tapped.


    [mvc release];  
}

设置模态视图的父按钮事件： -

-(void)settingParentButton:(UIImageView *)imageView {
    imageView1=imageView;
}

并在模态视图的索引路径上选择了行： -

-(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{ 
    NSLog(imageView1.tag);
    if (indexPath.row==0) {
        [imageView1 setImage:[UIImage imageNamed:[nsmResult objectAtIndex:indexPath.row]] ];    
    }
    if (indexPath.row==1) {
        [imageView1 setImage:[UIImage imageNamed:[nsmResult objectAtIndex:indexPath.row]] ];    
    }
    if (indexPath.row==2) {
        [imageView1 setImage:[UIImage imageNamed:[nsmResult objectAtIndex:indexPath.row]] ];

    }
    if (indexPath.row==3) {
        [imageView1 setImage:[UIImage imageNamed:[nsmResult objectAtIndex:indexPath.row]] ];    
    }
    [pop2 dismissPopoverAnimated:YES];
}

请帮助。这是标签问题，请告诉我如何查看正在进行哪个标签，我可以通过该标签查看图片。请回答。

Answer 1

在创建内存分配时，在该imageview中，不应该自动释放，在dealloc中释放你的记忆，你的预期图像将被放置在你的出现中。

- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info



{
    UIImage *im =  [info objectForKey:UIImagePickerControllerOriginalImage];


    self.imageView.image = im;

    UIImageWriteToSavedPhotosAlbum(im, nil, nil, nil);

    imageView.contentMode = UIViewContentModeScaleAspectFit;
    [[picker parentViewController] dismissModalViewControllerAnimated:YES];
}

@interface testpViewController : UIViewController
<UIImagePickerControllerDelegate, UINavigationControllerDelegate>

{
    IBOutlet    UIImageView     *imageView;
}

@property   (nonatomic, retain) UIImageView     *imageView;

无法在图像视图上设置图像

1 个答案: