Question

我在工匠命令中创建了一个模型工厂：

public function handle()
    {
        if (!$this->isDevelopment()) {
            $this->errorMessageSwitchEnvToDev();
            return;
        }

        $userId          = $this->ask('Please specifiy user_id you want to add the payouts to.',2148);
        $numberOfPayouts = $this->ask('How many payouts you want to generate?', 10);

        factory(\App\Payout::class, $numberOfPayouts)->create([
            'user_id' => $userId,
        ]);
    }

技术人员可以在我的本地桌面上工作，但是在我的测试服务器上部署后就无法工作。

我收到以下错误消息：

InvalidArgumentException  : Unable to locate factory with name [100] [App\Payout].

  at /www/htdocs/w0146a6f/dev/dev4.partner.healyworld.net/releases/20201014150056/vendor/laravel/framework/src/Illuminate/Database/Eloquent/FactoryBuilder.php:269
    265|      */
    266|     protected function getRawAttributes(array $attributes = [])
    267|     {
    268|         if (! isset($this->definitions[$this->class][$this->name])) {
  > 269|             throw new InvalidArgumentException("Unable to locate factory with name [{$this->name}] [{$this->class}].");
    270|         }
    271| 
    272|         $definition = call_user_func(
    273|             $this->definitions[$this->class][$this->name],

  Exception trace:

  1   Illuminate\Database\Eloquent\FactoryBuilder::getRawAttributes([])
      /www/htdocs/w0146a6f/dev/dev4.partner.healyworld.net/releases/20201014150056/vendor/laravel/framework/src/Illuminate/Database/Eloquent/FactoryBuilder.php:292

  2   Illuminate\Database\Eloquent\FactoryBuilder::Illuminate\Database\Eloquent\{closure}()
      /www/htdocs/w0146a6f/dev/dev4.partner.healyworld.net/releases/20201014150056/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Concerns/GuardsAttributes.php:122

我与特使进行部署。

我的工厂在database/factories/PayoutFactory.php

中定义

<?php

$factory->define(\App\Payout::class, function (Faker\Generator $faker) {


    return [
        'user_id' => function () {
            return factory(App\User::class)->create()->id;
        },
        'amount' => $faker->randomFloat(2),
        'req_amount' => 0,
        'tax_amount' => 0,
        'withheld' => 0,
        'vat_rate' => $faker->randomNumber(2),
        'released_amount' => $faker->randomFloat(2),
        'released_amount_local_currency' => $faker->randomFloat(2),
        'status' => 'released',
        'flag' => 0,
        'created_at' => $faker->dateTimeBetween('-6 months', 'now'),
    ];
});

但是，它将无法在生产中使用。我已经清除了缓存，路由并调用了composer dump-autoload，但是由于相同的问题仍然失败。

有什么建议吗？

我也阅读了Laravel 5.2: Unable to locate factory with name [default]的所有答案，但没有一个起作用。

Answer 1

请注意：

Unable to locate factory with name [100]

看来factory()愿意使用状态而不是数量。在这种情况下，它正在寻找名为（string）“ 100”的工厂状态，而不是（int） 100

将您的金额变量设为整数

    $numberOfPayouts = (int) $this->ask('How many payouts you want to generate?', 10);

或者，尝试使用->times($amount)方法更明确。

无法找到生产名称的工厂？

1 个答案: