strcmp（）返回-1而不是0

Question

我以为我了解PHP的strcmp()函数，直到我编写了在为'1'拍摄时生成'0'的代码。 我正在测试的代码使用$CSVStandard将.gz文件第一行中的字符串与字符串变量strcmp()进行比较。

$gzstr = 'user_2020-06-24_000test.csv.gz';
$openFile = gzopen($gzstr,"r");
$gzgetsBuffer = gzgets($openFile);
gzclose($openFile);

$CSVStandard ='"user_id","create_time","last_process_day","expiry_time","billing_zip","shipping_zip","domain","os_type","delivery_date","fwd_enabled_date"';
$c=(strcmp($CSVStandard,$gzgetsBuffer));

echo "gzgetsBuffer:"."<br>".$gzgetsBuffer."<br>";
echo "CSVStandard:"."<br>".$CSVStandard."<br>";
echo "Output of strcmp():   ".$c."<br>";

echo "Reverse parameters in strcmp():  ".(strcmp($gzgetsBuffer,$CSVStandard));

我也颠倒了参数，得到了-1。有没有隐藏的东西或gzgets()使用的指针，我看不到？

以下是输出：

Output gzgets:
"user_id","create_time","last_process_day","expiry_time","billing_zip","shipping_zip","domain","os_type","delivery_date","fwd_enabled_date"
CSVStandard:
"user_id","create_time","last_process_day","expiry_time","billing_zip","shipping_zip","domain","os_type","delivery_date","fwd_enabled_date"
Output of strcmp(): -1
Reverse parameters in strcmp(): 1

Answer 1

我认为您的代码是正确的。但是user_2020-06-24_000test.csv文件具有一些隐藏的内容，例如换行'\ n'。