这是我需要在个人项目中实现的新要求。我已成功使用聚合(previous question)加入了两个集合。现在,我需要加入一个新集合。请参见下面的代码:
学生模型:
{
fullname: { type: String, required: true },
email: { type: String, required: true },
}
考试模式:
{
test: { type: String, required: false },
top10: [
type: {
studentId: { type: String, required: true },
score: { type: Number, required: false },
}
]
}
汇总集合:
db.exams.aggregate([
{ $unwind: "$top10" },
{
$lookup: {
from: "students",
localField: "top10.studentId",
foreignField: "_id",
as: "students"
}
},
{ $addFields: { students: { $arrayElemAt: ["$students", 0] } } },
{
$group: {
_id: "$_id",
test: { $first: "$test" },
students: {
$push: {
studentId: "$top10.studentId",
score: "$top10.score",
fullname: "$students.fullname"
}
}
}
}
])
现在,第三个收藏集称为 Teacher (老师)。
教师模型:
{
fullName: { type: String, required: false },
studentId: { type: String, required: false }
}
预期输出应为:
{
"test": "Sample Test #1",
"students": [
{
"studentId": "5f22ef443f17d8235332bbbe",
"fullname": "John Smith",
"score": 11,
"teacher": "Dr. Hofstadter"
},
{
"studentId": "5f281ad0838c6885856b6c01",
"fullname": "Erlanie Jones",
"score": 9,
"teacher": "Mr. Roberts"
},
{
"studentId": "5f64add93dc79c0d534a51d0",
"fullname": "Krishna Kumar",
"score": 5,
"teacher": "Ms. Jamestown"
}
]
}
一种帮助。谢谢!
答案 0 :(得分:1)
您可以在$ group管道之前添加另外2个管道,
$lookup
与老师一起加入收藏集$addFields
将数组转换为对象$group
在学生数组中添加老师姓名 {
$lookup: {
from: "teacher",
localField: "top10.studentId",
foreignField: "studentId",
as: "students.teacher"
}
},
{
$addFields: {
"students.teacher": { $arrayElemAt: ["$students.teacher", 0] }
}
},
{
$group: {
_id: "$_id",
test: { $first: "$test" },
students: {
$push: {
studentId: "$top10.studentId",
score: "$top10.score",
fullname: "$students.fullname",
teacher: { $ifNull: ["$students.teacher.fullname", ""] }
}
}
}
}