Django管理员list_filter:基于用户

时间:2020-10-13 09:40:24

标签: django django-admin django-admin-filters

问题类似于Django "list_filter" based on the admin queryset。我需要根据当前用户使用list_filter。但是在我的情况下,字段跨度关系使用__查找。在RelatedFieldListFilter上没有有用的“查找”方法。我的方法产生了下一个代码:

def custom_titled_filter(title):
    class Wrapper(admin.FieldListFilter):
        def __new__(cls, field, request, *args, **kwargs):
            instance = admin.FieldListFilter.create(field, request, *args, **kwargs)
            instance.title = title

            rel_model = field.remote_field.model
            qs = rel_model._default_manager.all()
            if not request.user.is_superuser:
                qs = qs.filter(user=request.user)
            choice_func = operator.attrgetter(
                field.remote_field.get_related_field().attname
                if hasattr(field.remote_field, 'get_related_field')
                else 'pk'
            )
            instance.lookup_choices = [
                (choice_func(x), str(x)) for x in qs
            ]
            return instance

    return Wrapper

当前版本的Django是否有更好的方法?

0 个答案:

没有答案