Question

我试图遍历以下数组，但未成功

我的方法正确吗？我对我的代码做了很多更改，可能不是原来的

我的尝试：

shinyApp(
  ui = fluidPage(
    selectInput("selection", 
                "Select Something:",
                list("Boring" = " ",
                     "Positive" = c("Cool", "Groovy", "Rad"),
                     "Basic" = " ",
                     "Taco" = c("Bell", "Hell")),
                selected = "Groovy"
    ),
    textOutput("result")
  ),
  server = function(input, output) {
    output$result <- renderText({
      paste("You chose", input$selection)
    })
  }
)

数组：

var gender = ["men", "women"];
var category = [
    "topwear",
    "bottomwear",
    "indianwear",
    "westernwear",
];

for (var i = 0; i < categories.length; i++) {
    for (var g = 0; g < gender.length; g++) {
        for (j = 0; j < categories[i][gender[g]].length; j++) {
            for (var c = 0; c < category.length; c++) {
                console.log("=======category========", category[c]);
                for (k = 0; k < categories[i][gender[g]][j][category[c]].length; k++) {
                    console.log(categories[i][gender[g]][j][category[c]][k]);
                }
            }
        }
    }
}

我需要获取数组中的名称。因为我需要在内部编写的代码中使用它最循环。

预先感谢

Answer 1

您的代码希望数组中的每个对象都具有men和women属性。但是这些属性位于单独的数组元素中。因此，您需要在尝试遍历其元素之前检查该属性是否存在。否则，您将尝试获取未定义属性的长度。

类似地，men或women数组中的每个对象只有一个属性，而不是category数组中的所有属性。

如果将变量分配给数组的当前元素，则循环将容易得多，因此不需要带有很多索引的长表达式，例如categories[i][gender[g]][j][category[c]][k]。并且使用forEach()可以简化这一过程。

var gender = ["men", "women"];
var category = [
  "topwear",
  "bottomwear",
  "indianwear",
  "westernwear",
];

var categories = [{
    men: [{
        topwear: [
          "men-topwear",
          "men-tshirts",
          "men-casual-shirts",
          "men-formal-shirts",
          "men-sweatshirts",
          "men-sweaters",
          "men-jackets",
          "men-blazers",
          "men-suits",
          "rain-jacket",
        ],
      },
      {
        bottomwear: [
          "men-jeans",
          "men-casual-trousers",
          "men-formal-trousers",
          "mens-shorts",
          "men-trackpants",
          "men-innerwear",
          "men-briefs-and-trunks",
          "men-boxers",
          "men-innerwear-vests",
          "men-nightwear",
          "men-thermals",
        ],
      },
    ],
  },
  {
    women: [{
        indianwear: [
          "women-kurtas-kurtis-suits",
          "ethnic-tops",
          "ethnic-wear-dresses-menu",
          "women-ethnic-bottomwear?f=categories%3AChuridar%2CLeggings%2CSalwar",
          "skirts-palazzos",
          "saree",
          "dress-material",
          "lehenga-choli",
          "dupatta-shawl",
          "women-ethnic-wear-jackets",
          "dresses?f=Gender%3Amen%20women%2Cwomen",
          "jumpsuits?f=Gender%3Amen%20women%2Cwomen",
        ],
      },
      {
        westernwear: [
          "women-shirts-tops-tees",
          "women-jeans-jeggings",
          "women-trousers",
          "women-shorts-skirts",
          "women-shrugs",
          "women-sweaters-sweatshirts",
          "women-jackets-coats",
          "women-blazers-waistcoats",
        ],
      },
    ],
  },
];

categories.forEach(catItem =>
  gender.forEach(genItem => {
    if (catItem[genItem]) {
      category.forEach(cat => {
        console.log("=======category========", cat);
        catItem[genItem].forEach(i => {
          if (i[cat]) {
            i[cat].forEach(x => console.log(x));
          }
        });
      });
    }
  })
);

无法遍历嵌套数组

1 个答案: