Question

我有一个使用Node.js，Express和Mongoose的后端。我正在尝试过滤嵌套在对象深处的文档数组，但是由于某种原因我无法访问该数组。路线> transform(df, Any_thrombosis = ifelse((Arterial_thrombosis == 'Yes') | (Venous_thrombosis == 'Yes'), 'Yes','No')) Patient_number Arterial_thrombosis Venous_thrombosis Any_thrombosis 1 1 Yes No Yes 2 2 No Yes Yes >包含已登录用户的附件文档。以下是mycode。

req

如果我router.post("/users/:id/accept", auth, async (req, res) => { try { // this filter is not working await req.user.friendRequests.filter((usr) => usr.owner !== req.params.id); await req.user.save(); res.send("Accepted") } catch (error) { res.status(400).send(error.message); } });会得到：

console.log(req.user)

如果我{ dateOfBirth: { date: 28, month: 'Sep', year: 2002 }, gender: 'male', cover: null, _id: 5f71c0674a54b03e70fcbe97, firstName: 'jake', lastName: 'sulli', email: 'hello2@gmail.com', friendRequests: [ _id: 5f71c1184a54b03e70fcbea0, owner: '5f71c0d14a54b03e70fcbe9b', friend: false, name: 'mad max' }, { _id: 5f76a7872b21c8208f3caa5f, owner: '5f742182931ab9125bc2ec9d', friend: false, name: 'shriya rai' }, { _id: 5f76f6fa85e74758e76cb1ec, owner: '5f76f541ab7a1255dc78987d', friend: false, name: 'dara singh' } ], }，则无法获得friendRequests数组，但可以得到console.log()，name和email。我要实现的是，如果gender，那么我想从数组中删除该对象。

Answer 1

您的friendRequests数组存在一些问题。

首先，您没有正确开始或结束对象。

friendRequests: [ 
    {        <=========================== Need another bracket 
      _id: 5f71c1184a54b03e70fcbea0,
      owner: '5f71c0d14a54b03e70fcbe9b',
      friend: false,
      name: 'mad max'
    },
    {
      _id: 5f76a7872b21c8208f3caa5f,
      owner: '5f742182931ab9125bc2ec9d',
      friend: false,
      name: 'shriya rai'
    },
    {
      _id: 5f76f6fa85e74758e76cb1ec,
      owner: '5f76f541ab7a1255dc78987d',
      friend: false,
      name: 'dara singh'
    }
  ]

第二，确保将_id转换为字符串

5f76f6fa85e74758e76cb1ec to "5f76f6fa85e74758e76cb1ec"

遍历和过滤Express和Mongoose中的数据

1 个答案: