当我尝试执行python manage.py migration时,出现以下错误:ValueError:字段'id'期望输入一个数字,但得到了'DEFAULT VALUE'。我的代码可能有什么问题。需要任何帮助,谢谢。
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/models/fields/__init__.py", line 1772, in get_prep_value
return int(value)
ValueError: invalid literal for int() with base 10: 'DEFAULT VALUE'
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "manage.py", line 21, in <module>
main()
File "manage.py", line 17, in main
execute_from_command_line(sys.argv)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/core/management/__init__.py", line 401, in execute_from_command_line
utility.execute()
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/core/management/__init__.py", line 395, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/core/management/base.py", line 328, in run_from_argv
self.execute(*args, **cmd_options)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/core/management/base.py", line 369, in execute
output = self.handle(*args, **options)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/core/management/base.py", line 83, in wrapped
res = handle_func(*args, **kwargs)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/core/management/commands/migrate.py", line 233, in handle
fake_initial=fake_initial,
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/migrations/executor.py", line 117, in migrate
state = self._migrate_all_forwards(state, plan, full_plan, fake=fake, fake_initial=fake_initial)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/migrations/executor.py", line 147, in _migrate_all_forwards
state = self.apply_migration(state, migration, fake=fake, fake_initial=fake_initial)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/migrations/executor.py", line 245, in apply_migration
state = migration.apply(state, schema_editor)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/migrations/migration.py", line 124, in apply
operation.database_forwards(self.app_label, schema_editor, old_state, project_state)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/migrations/operations/fields.py", line 112, in database_forwards
field,
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/backends/sqlite3/schema.py", line 328, in add_field
self._remake_table(model, create_field=field)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/backends/sqlite3/schema.py", line 189, in _remake_table
self.effective_default(create_field)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/backends/base/schema.py", line 303, in effective_default
return field.get_db_prep_save(self._effective_default(field), self.connection)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/models/fields/related.py", line 939, in get_db_prep_save
return self.target_field.get_db_prep_save(value, connection=connection)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/models/fields/__init__.py", line 821, in get_db_prep_save
return self.get_db_prep_value(value, connection=connection, prepared=False)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/models/fields/__init__.py", line 2365, in get_db_prep_value
value = self.get_prep_value(value)
File "/home/risper/django_projects/env01/lib/python3.6/site-packages/django/db/models/fields/__init__.py", line 1776, in get_prep_value
) from e
ValueError: Field 'id' expected a number but got 'DEFAULT VALUE'.
这是我的模型py文件,其中定义了我的模型:
from django.db import models
# Create your models here.
class ImageModel(models.Model):
imagefile=models.ImageField(upload_to='images', null=True, verbose_name="")
def __str__(self):
return str(self.imagefile)
class Diseases(models.Model):
disease_name=models.CharField(max_length=100)
description=models.CharField(max_length=100)
def __str__(self):
return self.disease_name
class Pestisides(models.Model):
pestiside_name=models.CharField(max_length=100)
directions=models.CharField(max_length=100)
price=models.CharField(max_length=100)
#test_location=
#time
disease= models.ManyToManyField(Disease)
def __str__(self):
return self.pestiside_name
class Predictions(models.Model):
#user= models.ForeignKey(User, on_delete=models.CASCADE,null=True)
disease = models.ForeignKey(Diseases,on_delete=models.CASCADE)
这是我的管理py文件,已在其中注册我的模型:
from django.contrib import admin
from .models import *
# Register your models here.
admin.site.register(ImageModel)
admin.site.register(Diseases)
admin.site.register(Pestisides)
admin.site.register(Predictions)
答案 0 :(得分:1)
首先疾病=模型。ManyToManyField(疾病)正确的模型名称。然后删除所有迁移,然后键入manage.py makemigrations并迁移命令。我希望它能起作用
class Pestisides(models.Model):
pestiside_name = models.CharField(max_length=100)
directions = models.CharField(max_length=100)
price = models.CharField(max_length=100)
# test_location=
# time
disease = models.ManyToManyField(Diseases)