根据ID及其属性在数组中合并对象

时间:2020-10-10 15:51:13

标签: javascript node.js underscore.js

我正在尝试使用相同的ID将两个多级对象合并到一个数组中。请帮忙。

对象的输入数组如下

{
    "data": [
       {
            "id": 1,
            "movieId": 1,
            "user": "test@test.com",
            "title": "test Project",
            "desc": "test 123 test 123test 123test 123test 123",
            "status": "Yes",
            "movies":[{
                "id": 1,
                "title": "Movie 1",
                "desc": "Movie 1 Movie 1 Movie 1 Movie 1",
                "status": "Yes",
                "images":[{
                        "id": 1,
                        "fileType": "image",
                        "fileName": "movie1.0.jpg",
                        "filePath": "images\\movie1.0.jpg",
                        "fileExten": ".jpg"
                    },
                    {
                        "id": 2,
                        "fileType": "image",
                        "fileName": "movie1.1.jpg",
                        "filePath": "images\\movie1.1.jpg",
                        "fileExten": ".jpg"
                }],
                "videos":[{
                        "id": 4,
                        "fileType": "video",
                        "fileName": "movie1.0.mp4",
                        "filePath": "videos\\movie1.0.mp4",
                        "fileExten": ".mp4"
                    },
                    {
                        "id": 5,
                        "fileType": "video",
                        "fileName": "movie1.1.mp4",
                        "filePath": "videos\\movie1.1.mp4",
                        "fileExten": ".mp4"
                }]
            }]
        },
        {
            "id": 1,
            "movieId": 3,
            "user": "test@test.com",
            "title": "test Project",
            "desc": "test 123 test 123test 123test 123test 123",
            "status": "Yes",
            "movies":[{
                "id": 3,
                "title": "Movie 3",
                "desc": "Movie 3 Movie 3 Movie 3 Movie 3",
                "status": "Yes",
                "images":[{
                    "id": 8,
                    "fileType": "image",
                    "fileName": "movie2.0.jpg",
                    "filePath": "images\\movie2.0.jpg",
                    "fileExten": ".jpg"
                }],
                "videos":[{
                        "id": 12,
                        "fileType": "video",
                        "fileName": "movie2.1.mp4",
                        "filePath": "videos\\movie2.1.mp4",
                        "fileExten": ".mp4"
                    },
                    {
                        "id": 16,
                        "fileType": "video",
                        "fileName": "movie2.2.mp4",
                        "filePath": "videos\\movie2.2.mp4",
                        "fileExten": ".mp4"
                    },
                    {
                        "id": 20,
                        "fileType": "video",
                        "fileName": "movie2.3.mp4",
                        "filePath": "videos\\movie2.3.mp4",
                        "fileExten": ".mp4"
                }]

            }]
        },{
            "id": 2,
            "user": "test@test.com",
            "title": "Test Project 2",
            "desc": "project2 123 project2  123 project2  123 project2  123 project2  123 ",
            "status": "Yes",
            "movies":[]
        }
    ]
}

上面的输出是由下面的代码产生的。

我需要合并两个具有相同ID的对象,以便内部电影数组也可以追加/合并。我已经尝试了许多方法,但是我无法获得期望的输出。请帮忙。

let groupList = [];
await Promise.all(
    await getGroups(user).map(async group => {
    group.movies = [await getMovies(group.movieId)];
    groupList.push(group);
    return groupList;
  }));

我自己找到了解决方法

解决方案:

-------------

下面的代码返回预期的确切期望输出。

await Promise.all(
    await getGroups(user).map(async (item, key) => {
      item.movies = [];
      groupList[key] = item;
      let movies = (item.movies_list) ?  item.movies_list.split(','): []; // it's looks like "1,2" string so converting it to array
      await Promise.all(
        movies.map( async (id, index) => {
            groupList[key].movies.push(await getMovies(id));
          return groupList;
        })
      ) 
    })
  );
console.log(groupList);

期望输出:

{
    "data": [
        {
            "id": 1,
            "user": "test@test.com",
            "title": "test Project",
            "desc": "test 123 test 123test 123test 123test 123",
            "status": "Yes",
            "movies":[{
                "id": 1,
                "title": "Movie 1",
                "desc": "Movie 1 Movie 1 Movie 1 Movie 1",
                "status": "Yes",
                "images":[{
                        "id": 1,
                        "fileType": "image",
                        "fileName": "movie1.0.jpg",
                        "filePath": "images\\movie1.0.jpg",
                        "fileExten": ".jpg"
                    },
                    {
                        "id": 2,
                        "fileType": "image",
                        "fileName": "movie1.1.jpg",
                        "filePath": "images\\movie1.1.jpg",
                        "fileExten": ".jpg"
                    }],
                    "videos":[{
                        "id": 4,
                        "fileType": "video",
                        "fileName": "movie1.0.mp4",
                        "filePath": "videos\\movie1.0.mp4",
                        "fileExten": ".mp4"
                    },
                    {
                        "id": 5,
                        "fileType": "video",
                        "fileName": "movie1.1.mp4",
                        "filePath": "videos\\movie1.1.mp4",
                        "fileExten": ".mp4"
                    }]

            },{
                "id": 3,
                "title": "Movie 3",
                "desc": "Movie 3 Movie 3 Movie 3 Movie 3",
                "status": "Yes",
                "images":[{
                    "id": 8,
                    "fileType": "image",
                    "fileName": "movie2.0.jpg",
                    "filePath": "images\\movie2.0.jpg",
                    "fileExten": ".jpg"
                    }],
                "videos":[{
                        "id": 12,
                        "fileType": "video",
                        "fileName": "movie2.1.mp4",
                        "filePath": "videos\\movie2.1.mp4",
                        "fileExten": ".mp4"
                    },
                    {
                        "id": 16,
                        "fileType": "video",
                        "fileName": "movie2.2.mp4",
                        "filePath": "videos\\movie2.2.mp4",
                        "fileExten": ".mp4"
                    },
                    {
                        "id": 20,
                        "fileType": "video",
                        "fileName": "movie2.3.mp4",
                        "filePath": "videos\\movie2.3.mp4",
                        "fileExten": ".mp4"
                }]
            }]
        },
        {
            "id": 2,
            "user": "test@test.com",
            "title": "Test Project 2",
            "desc": "project2 123 project2  123 project2  123 project2  123 project2  123 ",
            "status": "Yes",
            "movies":[]
        }
    ]
}

1 个答案:

答案 0 :(得分:1)

使用Map

var moviesData = { "data": [ { "id": 1, "movieId": 1, "user": "test@test.com", "title": "test Project", "desc": "test 123 test 123test 123test 123test 123", "status": "Yes", "movies":[{ "id": 1, "title": "Movie 1", "desc": "Movie 1 Movie 1 Movie 1 Movie 1", "status": "Yes", "images":[{ "id": 1, "fileType": "image", "fileName": "movie1.0.jpg", "filePath": "images\\movie1.0.jpg", "fileExten": ".jpg" }, { "id": 2, "fileType": "image", "fileName": "movie1.1.jpg", "filePath": "images\\movie1.1.jpg", "fileExten": ".jpg" }], "videos":[{ "id": 4, "fileType": "video", "fileName": "movie1.0.mp4", "filePath": "videos\\movie1.0.mp4", "fileExten": ".mp4" }, { "id": 5, "fileType": "video", "fileName": "movie1.1.mp4", "filePath": "videos\\movie1.1.mp4", "fileExten": ".mp4" }] }] }, { "id": 1, "movieId": 3, "user": "test@test.com", "title": "test Project", "desc": "test 123 test 123test 123test 123test 123", "status": "Yes", "movies":[{ "id": 3, "title": "Movie 3", "desc": "Movie 3 Movie 3 Movie 3 Movie 3", "status": "Yes", "images":[{ "id": 8, "fileType": "image", "fileName": "movie2.0.jpg", "filePath": "images\\movie2.0.jpg", "fileExten": ".jpg" }], "videos":[{ "id": 12, "fileType": "video", "fileName": "movie2.1.mp4", "filePath": "videos\\movie2.1.mp4", "fileExten": ".mp4" }, { "id": 16, "fileType": "video", "fileName": "movie2.2.mp4", "filePath": "videos\\movie2.2.mp4", "fileExten": ".mp4" }, { "id": 20, "fileType": "video", "fileName": "movie2.3.mp4", "filePath": "videos\\movie2.3.mp4", "fileExten": ".mp4" }] }] },{ "id": 2, "user": "test@test.com", "title": "Test Project 2", "desc": "project2 123 project2  123 project2  123 project2  123 project2  123 ", "status": "Yes", "movies":[] } ] }

let makeMap = new Map();
moviesData.data.forEach((o) => {
  if (makeMap.has(o.id)) {
    let oldmov = makeMap.get(o.id).movies;
    o.movies = [...oldmov, ...o.movies];
    makeMap.set(o.id, o);
  } else makeMap.set(o.id, o);
});

//console.log(makeMap.entries());
console.log([...makeMap]);