我的目标:
我希望在我的 Flutter应用程序 中调用 Cloud Function ,该函数会检索 JSON obj 来自 Python-FastAPI服务器 ,并在 Alert Dialogue 中显示内容。
错误:
我的flapp应用程序中的Callable Function Service收到null。我的警报对话框显示由我的代码触发的“空值错误”。
- 在可调用的Http函数
中从客户端(Flutter APP)接收数据- 调用Python API =>返回到返回给客户端的Cloud Function
云功能:
exports.getRandomPassword = functions.https.onCall(async (data, context) => {
const useSymbols = data.useSymbols;
const pwLength= data.pwLength;
const debug ={
received_data_type: typeof data,
received_data:data,
pwLen_type: typeof pwLength,
pwLength,
useSymbols_type:typeof useSymbols,
useSymbols,
}
console.log(debug);
await callAPI(pwLength,useSymbols).then((res:any) =>{
console.log(`Resulting Payload: ${res}`);
return res});
});
Python-FastAPI调用:
async function callAPI(pwLength: any, useSymbols: any) {
// BUILD URL STRING WITH PARAMS
const ROOT_URL = `http://[IP_Address]/password?pwd_length=${pwLength}&use_symbols=${useSymbols}`;
let res;
// let password: any; // password to be received
await http.get(ROOT_URL)
.then((response: any) => {
console.log("TO APP "+JSON.stringify(response));
console.log(response.getBody());
res = response.getBody() as Map<any, any>;
})
.catch((err: any) => {
console.log(err);
res= err;
});
return res;
}
生成的有效负载可以正常运行,如我的日志所示:
在按钮上单击Flutter:
onPressed: () async {
// call cloud function & use set state to store pw
await getPassword().then((String result) {
setState(() {
password = result;
});
});
showDialog(
context: context,
builder: (context) => DisplayPassword());
},
我的Flutter getPassword()函数:
Future<String> getPassword() async {
var pw;
final HttpsCallable callable = new CloudFunctions()
.getHttpsCallable(functionName: 'getRandomPassword')
..timeout = const Duration(seconds: 30);
try {
await callable.call(
<String, dynamic>{
'pwLength': 10,
'useSymbols': true,
},
).then((value) {
print(value.data);
print(value.data.runtimeType);
pw = value.data;
return pw;
});
} on CloudFunctionsException catch (e) {
print('caught firebase functions exception');
print('Code: ${e.code}\nmessage: ${e.message}\ndetails: ${e.details}');
return '${e.details}';
} catch (e) {
print('caught generic exception');
print(e);
return 'caught generic exception\n$e';
}
}
我的显示密码功能:
class DisplayPassword extends StatelessWidget {
final String pw = (_MyPasswordGenPageState().password == null)
? 'null value error'
: _MyPasswordGenPageState().password;
@override
Widget build(BuildContext context) {
return AlertDialog(
title: Text(pw),
);
}
}
注意 * 我想将密码检索保留为Cloud Function,因此可以在Web应用程序和移动应用程序上使用。但是,如果有更好的解决方案,我愿意重构整个操作。
答案 0 :(得分:0)
解决方案:
- 将构造函数用于无状态小部件
- 避免使用
.then()
- 在
Promise.resolve()
函数中调用时,Cloud Functions应该返回async
。
在按钮上单击:
dynamic result =
await callable.call(<String, dynamic>{
'pwLength': 10,
'useSymbols': true,
//await the result before continuing
});
setState(() {
// convert hashmap to list and get first val
password = result.data.values.toList()[0];
isLoading = false; // remove loading indicator
});
showDialog(
context: context,
builder: (context) =>
DisplayPassword(password));
为了便于阅读,我在上面的代码中删除了异常处理
显示警报对话框:
class DisplayPassword extends StatelessWidget {
var password; // check if null
DisplayPassword(this.password); // constructor
@override
Widget build(BuildContext context) {
// make sure null value isn't being passed to alert dialog widget
if (password == null) {
password = 'null value error';
}
return AlertDialog(
title: Text(password),
);
}
}
云功能:
exports.getRandomPassword = functions.https.onCall(async (data, context) => {
const useSymbols = data.useSymbols;
const pwLength= data.pwLength;
let password;
password = await callAPI(pwLength,useSymbols);
const debug ={
received_data_type: typeof data,
received_data:data,
pwLen_type: typeof pwLength,
pwLength,
useSymbols_type:typeof useSymbols,
useSymbols,
ResultingPayloadType: typeof password,
ResultingPayload: password,
}
console.log(debug);
return Promise.resolve(password)
});
async function callAPI(pwLength: any, useSymbols: any) {
// BUILD URL STRING WITH PARAMS
const ROOT_URL = `http://[My_Api_IP_Address]/password?pwd_length=${pwLength}&use_symbols=${useSymbols}`;
const res = await http.get(ROOT_URL);
console.log(res.getBody());
return res.getBody() as Map<String , any>;
}