Question

我有一个像这样的数据框。

key            values
Interface       InterfaceA
State           Up
Line Status     Up
ID              9000
Interface       InterfaceB
State           Down
Line Status     Down
ID              9001

我想将其转变为这样

Interface        State        Line Status       ID
InterfaceA        Up             Up             9000
InterfaceB        Down           Down           9001

我尝试使用loc逐列插入，但是当到达第二列时

ValueError：无法从重复的轴重新索引

出现上述错误。

final_df['Interface'] = commands_df.loc[commands_df['key'].str.contains('Interface'), 'values']
final_df['State'] = commands_df.loc[commands_df['key'].str.contains('State'), 'values'] <-- Error starts here

ValueError: cannot reindex from a duplicate axis

Answer 1

df = df.assign(Interface=df[df['key'] == 'Interface']['values']).ffill()
print(df.pivot(index='Interface', columns='key', values='values').drop(columns='Interface'))

打印：

key           ID Line Status State
Interface                         
InterfaceA  9000          Up    Up
InterfaceB  9001        Down  Down

Answer 2

这是一个可能的解决方案-

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        });
    }
}

import pandas as pd

df = pd.DataFrame(data=['InterfaceA', 'Up', 'Up', 9000, 'InterfaceB', 'Down', 'Down', 9001],
                  index=['Interface', 'State', 'Line Status', 'ID', 'Interface', 'State', 'Line Status', 'ID'])

df = df.T
print(df.groupby(df.columns.values, axis=1).agg(lambda x: x.values.tolist()).sum().apply(pd.Series).T)

此answer

的积分

Answer 3

带有set_index和cumcount的简单unstack

df_final = df.set_index([df.groupby('key').cumcount(),'key'])['values'].unstack()

Out[423]:
key    ID   Interface Line-Status State
0    9000  InterfaceA          Up    Up
1    9001  InterfaceB        Down  Down

另一种方法是使用pd.crosstab

df_final = pd.crosstab(df.groupby('key')['values'].cumcount(), 
                       df['key'], 
                       df['values'], aggfunc='first')

Out[424]:
key      ID   Interface Line-Status State
row_0
0      9000  InterfaceA          Up    Up
1      9001  InterfaceB        Down  Down

熊猫用行值填充列

3 个答案: