Question

我正在一个小型Web应用程序上，我想使用Codeigniter将多个动态字段值插入数据库中，无法将addmore和type字段值插入数据库中？我要将单个或多个值插入数据库吗？

HTML

     <form name="add_name" method="POST" action="AddMoreController/storePost">

        <div class="table-responsive">  
            <table class="table table-bordered" id="dynamic_field">  
                <tr>  
                    <td><input type="text" name="addmore[]" placeholder="Enter your Name" class="form-control name_list" required="" /></td>

                </tr>
                <tr>
                    <td><input type="text" name="type[]" placeholder="Enter your Name" class="form-control name_list" required="" /></td>
                    <td><button type="button" name="add" id="add" class="btn btn-success">Add More</button></td>
                </tr>

            </table>
            <input type="submit" name="submit" id="submit" class="btn btn-info" value="Submit" />  
        </div>


     </form>

jQuery

    $(document).ready(function(){      
  var i=1;  


  $('#add').click(function(){
       i++;
       $('#dynamic_field').append('<tr id="row'+i+'" class="dynamic-added"><td><input type="text" name="addmore[]" placeholder="Enter your Name" class="form-control name_list" required /></td></tr><tr id="row'+i+'" class="dynamic-added"><td><input type="text" name="type[]" placeholder="Enter your Name" class="form-control name_list" required /></td><td><button type="button" name="remove" id="'+i+'" class="btn btn-danger btn_remove">X</button></td></tr>');
  });


  $(document).on('click', '.btn_remove', function(){  
       var button_id = $(this).attr("id");   
       $('#row'+button_id+'').remove();  
  });  


});

控制器

public function storePost()
 {
    $nameArr = $_POST['addmore'];
    $emailArr = $_POST['type'];
    if(!empty($nameArr)){
        for($i = 0; $i < count($nameArr); $i++){
            if(!empty($nameArr[$i])){
                $data['name'] = $nameArr[$i];
                $data['type'] = $emailArr[$i];

                $this->db->insert('tagslist',$data);
            }
        }
    }

   print_r('Record Added Successfully.');
}

Answer 1

更改您的控制器代码：-

    public function storePost(){
    
    $nameArr = $_POST['addmore'];
    $emailArr = $_POST['type'];
    if(!empty($nameArr)){
        for($i = 0; $i < count($nameArr); $i++){
            if(!empty($nameArr[$i])){
                $data = array(
                    'col_name' => $nameArr[$i],
                    'col_name' => $emailArr[$i]);

                $this->db->insert('tagslist',$data);
            }
        }
    }

   print_r('Record Added Successfully.');
}

Codeigniter是否将多个输入字段动态插入数据库？

1 个答案: