Question

我只需要选择MIN日期为7天前的行。我有带发票的客户，发票有到期日。我可以为每个客户选择这些发票的最短到期日期。我现在陷入困境，因为我无法只选择过期最晚7天的客户。

这就是我所拥有的：

select
 customerID,
 MIN(dueDate) as min_due_date
 from invoices
 where (invoiceStatus NOT IN ('PaidPosted','Cancelled'))
 and (entity = 'HQ')
 group by (customerID)

我尝试添加：

and min_due_date = dateadd(day, -7, SYSDATE())

这不起作用。我在做什么错了？

谢谢。

Answer 1

使用having子句来过滤最小日期：

select customerID, min(dueDate) as min_due_date
from invoices
where invoiceStatus not in ('PaidPosted', 'Cancelled') and
      entity = 'HQ'
group by customerID
having min(duedate) = current_date - interval '7 day';

请注意，日期函数高度依赖于数据库。上面是标准的SQL，但是确切的语法取决于您使用的数据库。

Answer 2

谢谢你，戈登，你让我走上了正轨！最终，这就是窍门：

select customerID, min(dueDate) as min_due_date
from invoices
where invoiceStatus not in ('PaidPosted', 'Cancelled') and
      entity = 'HQ'
having MIN(dueDate) = trunc(sysdate) -7
group by customerID

SQL-MIN日期恰好是7天前

2 个答案: