我有一个这样创建的菜单:
Locale currentLocale = Locale.getDefault();
System.out.println(currentLocale.getDisplayLanguage());
System.out.println(currentLocale.getDisplayCountry());
System.out.println(currentLocale.getLanguage());
System.out.println(currentLocale.getCountry());
System.out.println(System.getProperty("user.country"));
System.out.println(System.getProperty("user.language"));
使用StackNavTitle:
import {createStackNavigator} from 'react-navigation';
const stackNav = createStackNavigator({
Main: {
screen: JourneeService,
navigationOptions: ({navigation}) => ({
headerTitle: <StackNavTitle title="Journée de Service " />,
headerStyle: {
backgroundColor: '#0088CE',
},
headerTintColor: '#fff',
headerTitleStyle: {
fontWeight: 'bold',
},
headerLeft: (
<TouchableOpacity
onPress={() => navigation.openDrawer()}
style={{width: '150%'}}>
<Icon name="ios-menu" size={35} color="#fff" style={{padding: 10}} />
</TouchableOpacity>
),
}),
}
在代码上我通过回调检索标题,我想动态设置标题,我该怎么做?
提前感谢您的答复
答案 0 :(得分:0)
您可以为标题提供一个函数,该函数根据文档接受三个参数,其中一个包含动态标题。这是我从文档中获取的示例,并使用您的标头组件进行更新
import {createStackNavigator} from 'react-navigation';
const stackNav = createStackNavigator({
Main: {
screen: JourneeService,
navigationOptions: ({navigation}) => ({
headerTitle: ({allowFontScaling, style, children})=> <StackNavTitle title={children.title} />,
headerStyle: {
backgroundColor: '#0088CE',
},
headerTintColor: '#fff',
headerTitleStyle: {
fontWeight: 'bold',
},
headerLeft: (
<TouchableOpacity
onPress={() => navigation.openDrawer()}
style={{width: '150%'}}>
<Icon name="ios-menu" size={35} color="#fff" style={{padding: 10}} />
</TouchableOpacity>
),
}),
}
您可以在这里https://reactnavigation.org/docs/4.x/stack-navigator#headertitle
找到更多信息