Linq to XML(在一个节点下获取特定值)

时间:2011-06-21 10:19:16

标签: c# linq-to-xml

我有一个xml,如下一个。

  <testing>
  <node01 name="node01Name">
    <node02s>
      <node02 name="1">
        <CustomProperties>
          <CustomProperty Name="ASCII File Name" Value="index.txt" FilterID="0" />
          <CustomProperty Name="ASCII Folder" Value="\\abc\cdf\aaaa" FilterID="0" />
          <CustomProperty Name="Delimiter" Value="CommaQuote" FilterID="0" />
          <CustomProperty Name="Duplicate Handling" Value="Replace if Dup" FilterID="0" />
          <CustomProperty Name="EMAILATTDOC" Value="1" FilterID="0" />
          <CustomProperty Name="EMAILATTINDEX" Value="0" FilterID="0" />
          <CustomProperty Name="EMAILOUTBODY" FilterID="0" />
          <CustomProperty Name="EMAILOUTCC" FilterID="0" />
        </CustomProperties>
      </node02>
      <node02 name="2">
        <CustomProperties>
          <CustomProperty Name="ASCII File Name" Value="index.txt" FilterID="0" />
          <CustomProperty Name="ASCII Folder" Value="\\abc\cdf\aaaa" FilterID="0" />
          <CustomProperty Name="Delimiter" Value="CommaQuote" FilterID="0" />
          <CustomProperty Name="Duplicate Handling" Value="Replace if Dup" FilterID="0" />
          <CustomProperty Name="EMAILATTDOC" Value="1" FilterID="0" />
          <CustomProperty Name="EMAILATTINDEX" Value="0" FilterID="0" />
          <CustomProperty Name="EMAILOUTBODY" FilterID="0" />
          <CustomProperty Name="EMAILOUTCC" FilterID="0" />
        </CustomProperties>
      </node02>
    </node02s>    
  </node01>  
</testing>

我需要在每个node02下获取每个CustomProperty。这是我的代码。

XDocument configparentXML = XDocument.Load("admin.xml");
string node = "node02";

var batchClasses = from batchClasse in configparentXML.Descendants(node)
                   select new ReadingXmlWithLinq
                   {
                       BatchClassName = batchClasse.Attribute("Name") != null ? batchClasse.Attribute("Name").Value : "",
                   };

foreach (var lv0 in batchClasses)
{
    node = "CustomProperty";
    var CustomProperties = from CustomProperty in configparentXML.Descendants(node)                                       
                           select new ReadingXmlWithLinq
                           {
                               CustomPropertyName = documentClasse.Attribute("Name") != null ? documentClasse.Attribute("Name").Value : ""
                           };
}

但是听到它返回所有CustomPropery值。如何获得node02的CustomerPropery?

非常感谢。

2 个答案:

答案 0 :(得分:3)

我会用XPath来解决这个问题:

var xmlString = @"<testing>...</testing>";
var doc = XDocument.Parse(xmlString);
var nav = doc.CreateNavigator();
var path = "/testing/node01/node02s/node02/CustomProperties/CustomProperty";
var nodeIterator = nav.Select(path);
var nodes =
    nodeIterator
        .Cast<XPathNavigator>()
        .Select(n=>XElement.Parse(n.OuterXml));

修改

要获取(例如)<node02 name="2">下的所有节点,您可以按如下方式更改路径:

var path=
   "/testing/node01/node02s/node02[@name=2]/CustomProperties/CustomProperty";

这是一个page of XPath examples,所以你可以看到什么是可能的。

答案 1 :(得分:1)

我不清楚你想要的数据,这里没有足够的信息可供使用。

相反,这是一个示例,说明如何选择所有node02元素并获取其名称和CustomProperty的名称。这会像您的代码一样选择 ALL node02 ALL 他们的CustomProperty。您实际上没有过滤任何内容,也没有指定您想要的节点或属性。你真正想要的东西令人困惑。相反,这是一个示例,说明如何执行您想要执行的操作:

XDocument doc = ...;
var batchClasses = doc.Descendants("node02")
    .Select(n => new
    {
        BatchClassName = (string)n.Attribute("name") ?? "",
        CustomPropertyNames = n.Descendants("CustomProperty")
            .Select(cp => (string)cp.Attribute("Name") ?? "")
            .ToList(),
        // Here's an example to select "EMAIL" custom property names
        EmailPropertyNames = n.Descendants("CustomProperty")
            .Select(cp => (string)cp.Attribute("Name") ?? "") // select the names...
            .Where(s => s.StartsWith("EMAIL"))                // that start with "EMAIL"
            .ToList(),                
    });