Question

我被困住了。看来这应该可行，但事实并非如此。

我正在尝试访问对象的键值，但是它不起作用。我以前已经做过，并且在堆栈溢出和其他地方已经读了很多东西，但是仍然无法正常工作。

这是我的代码：


  var validate = UrlFetchApp.fetch(url, options);
  
  Logger.log('validate = ' + validate);
  Logger.log("validate['response'] = " + validate["response"]);
  Logger.log('validate.response = ' + validate.response);
  Logger.log("validate.['done'] = " + validate["done"]);
  Logger.log("validate.done = " + validate.done);
  
  var validateObj = JSON.stringify(JSON.parse(validate));
  
  Logger.log("validateObj = " + validateObj);
  Logger.log("validateObj.response = " + validateObj.response);
  Logger.log("validateObj.done = " + validateObj.done);

这是日志：

validate = {
  "done": true,
  "response": {
    "@type": "type.googleapis.com/google.apps.script.v1.ExecutionResponse",
    "result": "Invalid Full Name.  Please enter a valid Full Name."
  }
}

validate['response'] = undefined

validate.response = undefined

validate.['done'] = undefined

validate.done = undefined

validateObj = {"done":true,"response":{"@type":"type.googleapis.com/google.apps.script.v1.ExecutionResponse","result":"Invalid Full Name.  Please enter a valid Full Name."}}

validateObj.response = undefined

validateObj.done = undefined

使用方括号表示法时，我也尝试过使用单引号和双引号。

有人可以帮我看看错误吗？

Answer 1

您正在尝试从字符串访问response和done属性，因此您将获得undefined。您尝试对响应执行JSON.parse，但随后将其JSON.stringify返回字符串，只需执行JSON.parse并访问属性

var validateObj = JSON.parse(validate); // Now you have a deserialized object

Logger.log("validateObj = " + validateObj); // You should get "validateObj = [object Object]"
Logger.log("validateObj.response = " + validateObj.response);
Logger.log("validateObj.done = " + validateObj.done);
Logger.log("validateObj[ 'response' ] = " + validateObj[ 'response' ] );
Logger.log("validateObj[ 'done' ]= " + validateObj[ 'done' ]);

访问JSON对象的键值

1 个答案: