Question

对于我的两个按钮，我想实现一个开关案例，点击后我得到以下错误如何解决？

void是一个无效的类型变量onClick 令牌上的语法错误“）”,;预期

这是我的代码。

        Button regmalebtn = (Button) findViewById(R.id.regmalebtn);
        Button regfemalebtn = (Button) findViewById(R.id.regfemalebtn);

    String gender; 
    gender = regmalebtn.getText().toString();
  public void onClick(View v) {

      switch(v.getId()){

      case R.id.regmalebtn:
    //    String gender; 
    //    gender = regmalebtn.getText().toString();
        gender.equals("M");
    //  request.addProperty("gender",gender );

           break;

      case R.id.regfemalebtn:
          gender = regfemalebtn.getText().toString();
            gender.equals("F");
            //request.addProperty("gender", gender);
           break;
           default:
               break;
      }
  }

Answer 1

您收到以下错误

令牌上的语法错误“）”,;预期

That means onClick() method is defined inside another method. It should be defined outside of any method in the same class

由于迪帕克

Answer 2

请删除默认：打破;

来自案件R.id.regfemalebtn：

代码必须如下所示：

public void onClick(View v) {

      switch(v.getId()){

      case R.id.regmalebtn:
    //    String gender; 
    //    gender = regmalebtn.getText().toString();
        gender.equals("M");
    //  request.addProperty("gender",gender );

           break;

      case R.id.regfemalebtn:
          gender = regfemalebtn.getText().toString();
            gender.equals("F");
            //request.addProperty("gender", gender);
           break;
      }
default:
               break;
  }

希望它可以帮到你

Answer 3

  public class Sample extends Activity implements OnClickListener
   {
      public void onCreate(Bundle bundle)
       {
           super.onCreate(bundle);
           setContentView(//ur layout);
           Button regmalebtn = (Button) findViewById(R.id.regmalebtn);
           Button regfemalebtn = (Button) findViewById(R.id.regfemalebtn);
           regmalebtn.setOnClickListener(this);
           regfemalebtn.setOnClickListener(this);
           String gender; 
           gender = regmalebtn.getText().toString();
       }//onCreate()
       public void onClick(View v) {
          switch(v.getId()){
               case R.id.regmalebtn:
                       //String gender; 
                       //    gender = regmalebtn.getText().toString();
                       gender.equals("M");
                        //  request.addProperty("gender",gender );
                      break;
               case R.id.regfemalebtn:
                       gender = regfemalebtn.getText().toString();
                       gender.equals("F");
                       //request.addProperty("gender", gender);
                      break;
               default:
                      break;
      }//onclick()
 }//Sample

试试这段代码..

Android：按钮onclick显示错误

3 个答案: