我有一个具有异步元素的类构造函数。稍后,当我创建此类的实例时,我想读取一个仅在构造函数完成100%时才存在的属性。我总是遇到问题Can not read property 'id' of undefined.
,我几乎可以肯定这是关于异步..等待的问题。
class NewPiecePlease {
constructor(IPFS, OrbitDB) {
this.OrbitDB = OrbitDB;
(async () => {
this.node = await IPFS.create();
// Initalizing OrbitDB
this._init.bind(this);
this._init();
})();
}
// This will create OrbitDB instance, and orbitdb folder.
async _init() {
this.orbitdb = await this.OrbitDB.createInstance(this.node);
console.log("OrbitDB instance created!");
this.defaultOptions = { accessController: { write: [this.orbitdb.identity.publicKey] }}
const docStoreOptions = {
...this.defaultOptions,
indexBy: 'hash',
}
this.piecesDb = await this.orbitdb.docstore('pieces', docStoreOptions);
await this.piecesDb.load();
}
...
}
稍后,我将创建此类的实例:
(async () => {
const NPP = new NewPiecePlease;
console.log(NPP.piecesDb.id);
// This will give 'undefined' error
})();
如何告诉NodeJS我希望new NewPiecePlease
完全完成? await console.log(NPP.piecesDb.id);
无济于事,这是可以理解的,因为它无法理解我在等待什么。正确的方法是什么?
答案 0 :(得分:1)
您可以为此使用工厂。它们非常适合进行复杂的,潜在的异步对象创建,并使构造函数保持整洁和专注。
class NewPiecePlease {
constructor(orbitdb, node, pieceDB) {
this.orbitdb = orbitdb;
this.node = node;
this.pieceDB = pieceDB;
}
static async create(IPFS, OrbitDB) {
const node = await IPFS.create();
const orbitdb = await OrbitDB.createInstance(node);
console.log("OrbitDB instance created!");
const defaultOptions = {
accessController: {
write: [orbitdb.identity.publicKey]
}
}
const docStoreOptions = { ...defaultOptions, indexBy: 'hash' };
const piecesDb = await orbitdb.docstore('pieces', docStoreOptions);
await piecesDb.load();
return new NewPiecePlease(orbitdb, node, piecedb);
}
}
您可以看到create方法完成了所有异步工作,并将结果传递到构造函数中,在该构造函数中,除了赋值和验证某些参数外,它实际上无需执行任何操作。
(async () => {
const NPP = await NewPiecePlease.create(IPFS, OrbitDB);
console.log(NPP.piecesDb.id);
// This will give 'undefined' error
})();