Question

我需要获得给定周的日期列表，其中包含该周的一个日期和开始日期。开始日可能是周一，周日等。

Answer 1

这是我认为有效的方式，不确定它是最有效的方式。 $ weekStart应设置为您认为本周的第一天（0 =星期日，1 =星期一等），$ date是输入日期。

$weekStart = 0;
$date = '2011-06-1';

$timestamp = strtotime($date);

$dayOfWeek = date('N', $timestamp);

$startDate = mktime(0,0,0, date('n', $timestamp), date('j', $timestamp) - $dayOfWeek + $weekStart, date('Y', $timestamp));
$endDate = mktime(0,0,0, date('n', $timestamp), date('j', $timestamp) - $dayOfWeek + 6 + $weekStart, date('Y', $timestamp));

echo 'Week runs from ' . date('Y-m-d', $startDate) . ' to ' . date('Y-m-d', $endDate);

Answer 2

替换$ dayOfWeek = date（'N'，$ timestamp）; $ dayOfWeek = date（'w'，$ timestamp）;因为如果使用星期天它会返回错误的星期日期。使用$ date ='2013-07-28'进行测试。

$weekStart = 0;
$date = '2011-06-1';

$timestamp = strtotime($date);

$dayOfWeek = date('w', $timestamp);

$startDate = mktime(0,0,0, date('n', $timestamp), date('j', $timestamp) - $dayOfWeek + $weekStart, date('Y', $timestamp));
$endDate = mktime(0,0,0, date('n', $timestamp), date('j', $timestamp) - $dayOfWeek + 6 + $weekStart, date('Y', $timestamp));

echo 'Week runs from ' . date('Y-m-d', $startDate) . ' to ' . date('Y-m-d', $endDate);

从给定日期开始计算一周的日期列表

2 个答案: