Question

我的功能如下，以及它的输出。

$results = mysql_query("SELECT * FROM tmsessions WHERE session_user_id ='".$_SESSION['user_id']."'");

    $count = mysql_num_rows($results);
    $username = mysql_fetch_assoc(mysql_query("SELECT user_fname FROM tmusers WHERE user_id = '".$_SESSION['user_id']."'"));

    $json_data = array( 'userID'=>$_SESSION['user_id'], 'userName'=>$username['user_fname'], 'total'=>$count );

    while($session = mysql_fetch_assoc($results))
    {
        $numListItems = mysql_num_rows(mysql_query("SELECT session_id, listing_unique_id FROM tmdata WHERE session_id = '".$session['session_id']."'"));

        $listItems = array('sessionID'=>$session['session_id'],
                           'sessionName'=>$session['session_name'],
                           'sessionCount'=>$numListItems,
                           'sessionDC'=>date('h:iA - M m y',strtotime($session['session_date_created'])),
                           'sessionDM'=>date('h:iA - M m y',strtotime($session['session_date_modified'])),
                           'sessionActive'=>$session['session_active']);

        array_push($json_data, $listItems);

    }

    return json_encode($json_data);

哪些外出：

{"0":
{"sessionID":"9",
 "sessionName":"dataName0",
 "sessionCount":100,
 "sessionDC":"12:11AM - Jun 06 11",
 "sessionDM":"01:00AM - Jan 01 70",
 "sessionActive":"1"},
 "1":
{"sessionID":"10",
 "sessionName":"dataName1",
 "sessionCount":100,
 "sessionDC":"05:04PM - Jun 06 11",
 "sessionDM":"01:00AM - Jan 01 70",
 "sessionActive":"1"},
 "userID":"1",
 "userName":"Ezra",
 "total":2}

我需要“0”：和“1”：位成为“listItem”：每个新的关联数组，但我不知道如何正确操作数组来获得它：（。

Answer 1

在PHP中，索引和关联数组被处理为相同的类型（即矩阵或一维数组，a [0]，a [1]，... a [N]，vs a ['one'] ，a ['two']，... a ['something']）。

使用array_push（）时，您不是在创建或添加关联哈希，而是在数组末尾创建索引值。

您可以使用您选择的名称直接分配，而不是使用array_push（）函数，例如

$listItems[$session['session_id']] = array('sessionID'=>$session['session_id'],
                           'sessionName'=>$session['session_name'],
                           'sessionCount'=>$numListItems,
                           'sessionDC'=>date('h:iA - M m y',strtotime($session['session_date_created'])),
                           'sessionDM'=>date('h:iA - M m y',strtotime($session['session_date_modified'])),
                           'sessionActive'=>$session['session_active']);

Answer 2

如果我正确理解你的问题，请尝试这个，而不是对不起，请告诉我我的理解错误？

$results = mysql_query("SELECT * FROM tmsessions WHERE session_user_id ='".$_SESSION['user_id']."'");

$count = mysql_num_rows($results);
$username = mysql_fetch_assoc(mysql_query("SELECT user_fname FROM tmusers WHERE user_id = '".$_SESSION['user_id']."'"));

$json_data = array( 'userID'=>$_SESSION['user_id'], 'userName'=>$username['user_fname'], 'total'=>$count );

while($session = mysql_fetch_assoc($results))
{
    $numListItems = mysql_num_rows(mysql_query("SELECT session_id, listing_unique_id FROM tmdata WHERE session_id = '".$session['session_id']."'"));

    $listItems = array('sessionID'=>$session['session_id'],
                       'sessionName'=>$session['session_name'],
                       'sessionCount'=>$numListItems,
                       'sessionDC'=>date('h:iA - M m y',strtotime($session['session_date_created'])),
                       'sessionDM'=>date('h:iA - M m y',strtotime($session['session_date_modified'])),
                       'sessionActive'=>$session['session_active']);

    $json_data['listItem'][] = $listItems;
}

return json_encode($json_data);

将关联数组插入另一个关联数组，维护键

2 个答案: