"react": "16.13.1",
"react-native": "0.63.2",
"@react-navigation/bottom-tabs": "^5.7.3",
"@react-navigation/compat": "^5.2.5",
"@react-navigation/material-bottom-tabs": "^5.2.15",
"@react-navigation/material-top-tabs": "^5.2.15",
"@react-navigation/native": "^5.7.3",
"@react-navigation/stack": "^5.9.0",
当我在设备上按回时,我想将数据传递回父屏幕。但是我得到了错误:-
TypeError:未定义不是对象(正在评估“ this.props.navigation”)
处理返回箭头标题不是问题。但是在智能手机的后退按钮本身上会出现此错误。
MainItem.js
onPressShowItem = (item, index) => {
this.props.navigation.navigate('ItemDetails', { FlatData: this.state.FlatData, FlatIndex: index, returnFromItems: this.returnFromItems });
}
returnFromItems = data => {
console.log('returned');
this.setState({ data });
}
ItemDetails.js
class ItemDetails extends PureComponent {
componentDidMount() {
BackHandler.addEventListener('hardwareBackPress', this.handleBackButton);
}
componentWillUnmount() {
BackHandler.removeEventListener('hardwareBackPress', this.handleBackButton);
}
/// PART OF ERROR APPEAR
handleBackButton() {
this.props.route.params.returnFromItems({ FlatData: this.state.FlatData });
return true;
}
// Handle back on header. No problem here
navigateBack = () => {
this.props.navigation.goBack();
this.props.route.params.returnFromItems({ FlatData: this.state.FlatData });
};
render() {
return (
const RenderBackAction = () => (
<TopNavigationAction icon={BackIcon} onPress={this.navigateBack} />
<TopNavigation title='Item Details' alignment='center' accessoryLeft={RenderBackAction} />
);
);
}
}
我尝试过,但最终出现错误:-
1. this.props.route.params.returnFromItems
2. this.props.navigation.state.params.returnFromItems
答案 0 :(得分:0)
您缺少对“ this”的引用
您可以将其绑定或更改如下功能
handleBackButton=()=> {
this.props.route.params.returnFromItems({ FlatData: this.state.FlatData });
return true;
}
当您返回true时,您将必须自行管理回溯,因此首选第二种方法。
您还可以使用现有的NavigationBack
handleBackButton=()=> {
this.navigateBack();
return true;
}