我有以下代码,想要简短些。对于!ChangesElem
,我必须进行循环。如何减少行数?
var ElementArray = document.getElementById('ob').getElementsByTagName("*");
for (var i = 0; i < ElementArray.length; i++) {
if (ElementArray[i] === e) {
var ChangesElem = "yes";
}
}
if (!ChangesElem) {
// do something...
}
答案 0 :(得分:2)
一方面,您可以获取带有查询字符串和#ob
的{{1}}所有后代的集合,然后检查集合querySelectorAll
是否为.includes
:
e
但是Node#contains
也可以正常工作:
const descendants = [...document.querySelectorAll('#ob *')];
if (!descendants.includes(e)) {
// do something
}
答案 1 :(得分:0)
text1 = "TKTID000"
text2 = "SITEIDNYL01101"
text3 = "VIPPASS123456"
text4 = "TKTSOWTEST"
sht1 = "TKTID"
sht2 = "SITEID"
sht3 = "VIPPASS"
sht4 = "TKTSOW "
input1 =text1.replace(sht1,'')
input2 =text2.replace(sht2,'')
input3 =text2.replace(sht3,'')
input4 =text4.replace(sht4,'')
print(input1)
print(input2)
print(input3)
print(input4)
将其缩短。您可以了解有关this link
的更多详细信息
Array.some