Question

不确定这是如何工作的。我有一个查询之间，但我如何运行查询以列出每天匹配的结果。例如，存在于2011-06-17,2011-06-18,2011-06-06和2011-06-20的enterys

SELECT lookup, `loc`, `octect1` ,`octect2` ,`octect3` ,`octect4`, date, time, count(`lookup`) as count FROM index 
WHERE date between '2011-06-17' AND '2011-06-20'
GROUP BY lookup
ORDER BY count DESC

由于

Answer 1

使用比较运算符代替BETWEEN：

SELECT lookup, `loc`, `octect1` ,`octect2` ,`octect3` ,`octect4`, 
       date, time, count(`lookup`) as count 
FROM index  
WHERE date > '2011-06-17' AND date < '2011-06-20' 
GROUP BY lookup 
ORDER BY count DESC

Mysql查询列表结果匹配每个日期

1 个答案: