此lambda是否可以捕获指针的副本?

时间:2020-09-30 20:16:47

标签: c++ lambda

在lambda中,我想捕获一个指针的副本,但是不能,因为它是一个静态变量(无法捕获):

#include <iostream>
#include <string>
#include <functional>

class Window
{public:
    Window(std::string name) : name(name) {}
    std::function<void(int)> eventHandlerFunction;
    std::string name;
};

Window* ptr;

int main()
{
    Window* wnd1 = new Window("wnd1");
    Window* wnd2 = new Window("wnd2");
    ptr = wnd1;

    wnd1->eventHandlerFunction = [=](int n) { std::cout << ptr->name; }; 
// I'd like to capture a copy of the ptr value to wnd1 through the ptr variable

   // BECAUSE THEN
    ptr = wnd2;

    // SOME TIME DOWN THE TRACK THE MOUSE CURSOR ROLLS OVER wnd1, calls eventHandlerFunction
    // and prints "wnd2" instead of "wnd1".
}

1 个答案:

答案 0 :(得分:6)

您可以使用lambda语法ptr复制[local_copy=variable_to_copy_from]的当前值:

#include <iostream>
#include <string>
#include <functional>

class Window {
public:
    Window(std::string name) : name(name) {}
    std::function<void(int)> eventHandlerFunction;
    std::string name;
};

Window* ptr;

auto get_ev_handler() {
    return [ptr=ptr](int n) { std::cout << n << ' ' << ptr->name << '\n'; };

    // You can name it something else if you'd like:
    //return [a_copy=ptr](int n) { std::cout << n << ' ' << a_copy->name << '\n'; };
}

int main() {
    Window* wnd1 = new Window("wnd1");
    Window* wnd2 = new Window("wnd2");

    ptr = wnd1;
    wnd1->eventHandlerFunction = get_ev_handler();
    ptr = wnd2;
    wnd2->eventHandlerFunction = get_ev_handler();
    ptr = nullptr;

    // here ptr == nullptr, but these still hold copies of the old values:
    wnd1->eventHandlerFunction(1);
    wnd2->eventHandlerFunction(2);
}