Question

我有一张包含以下字段和数据的表格。

RefNo Year Month Code
1     2010  7     A
2     2009  10    B
3     2010  8     A
4     2010  5     B

从这里我可以找出特定代码的最大值（年，月）。结果必须是

3   2010  8 A
1   2010  7 B

请帮我解决这个问题。

Answer 1

SELECT
  *
FROM
(
  SELECT
    ROW_NUMBER() OVER (PARTITION BY Code ORDER BY Year DESC, Month DESC) AS row_number,
    *
  FROM
    myTable
)
  AS orderedTable
WHERE
  row_number = 1

编辑现在，对于在MySQL中工作的版本......

SELECT
  *
FROM
  myTable
WHERE
  Year * 12 + Month = (SELECT MAX(Year * 12 + Month) FROM myTable AS lookup WHERE Code = myTable.Code)

编辑访问SQL后，可以确认这更快......

WHERE
    Year  = (SELECT MAX(Year)  FROM myTable AS lookup WHERE Code = myTable.Code)
AND Month = (SELECT MAX(Month) FROM myTable AS lookup WHERE Code = myTable.Code AND Year = myTable.Year)

Answer 2

这对你有用吗？我们的想法是将Year和Month组合成SQL可以获取MAX的内容，然后将表连接到自身的这个修改版本。

SELECT OriginalTable.RefNo, OriginalTable.Year, OriginalTable.Month, OriginalTable.Code
FROM table OriginalTable,
     (SELECT Code, MAX(Year*100 + Month) AS CombinedDate
      FROM table
      GROUP BY Code) AS MaximumResults
WHERE OriginalTable.Code = MaximumResults.Code
AND OriginalTable.Year = MaximumResults.CombinedDate / 100
AND OriginalTable.Month = MaximumResults.CombinedDate % 100

这个想法在这里有更详细的解释：http://www.techonthenet.com/sql/max.php

Answer 3

假设您的表名是“table1”，那么

select * from
(select * from table1 where Year in (select max(Year) from table1)) abc
where Month not in (select min(Month) from abc)

Answer 4

我有解决方案：

Select Month(B.NewDate) Mon, Year(B.NewDate) Year, Code, PK
from T1 A ,
(Select Max(Str_To_Date(Concat('01',',',Month,',',Year), '%d,%m,%Y')) as NewDate, Code C
from T1 group by Code) B
Where PK = (Select PK from T1
                where Year = Year(B.NewDate) and Month = Month(B.NewDate)  and Code = A.Code)
and A.Code = C
group by Code

在mysql查询中找到多行的最大列集

4 个答案: