开玩笑拒绝功能失败

Question

const fetchDataPromise = (cal) => Promise.reject("error");    

test("the fetch fails with an error2", async () => {
      await expect(fetchDataPromise()).rejects.toThrow("error");
    });

Expected substring: "error"

Received function did not throw

  25 | 
  26 | test("the fetch fails with an error2", async () => {
> 27 |   await expect(fetchDataPromise()).rejects.toThrow("error");
     |                                            ^
  28 | });

Answer 1

我认为您想要await expect(fetchDataPromise()).rejects.toEqual("error");

这将断言拒绝的值是“错误”。 toThrow方法断言已抛出Error，即throw new Error('fart bubble')。